Interference and principle of superposition is considered one the most difficult concept.
22 Questions around this concept.
Three harmonic waves having equal frequency v and same intensity $\mathrm{I}_0$, have phase angles $0, \frac{\pi}{4}$ and $-\frac{\pi}{4}$, respectively. When they are superimposed the intensity of the resultant wave is close to:
Two waves are passing through a region in the same direction at the same time. If the equation of these waves are , then the amplitude of the wave for
is-
A standing wave is maintained in a homogenous string of cross-sectional area S and density ρ. It is formed by the superposition of two waves density ρ, travelling in opposite directions given by the equation and
. The total mechanical energy confined between the sections corresponding to the adjacent anti-nodes is-
A travelling wave represented by is superimposed on another wave represented by
, The resultant is
Two waves,
superimpose to produce a stationary wave, then
The interference pattern is obtained with two coherent light sources of intensity ratio 4. In the interference pattern, the ratio will be?
When two waves of same frequency, the same wavelength, same velocity (nearly equal amplitude) move in the same direction, Their superimposition results in interference. Due to interference, the resultant intensity of sound at that point is different from the sum of intensities due to each wave separately. This modification of intensity due to the superposition of two or more waves is called interference.
The displacement at any time due to any number of waves meeting simultaneously at a point in a medium is the vector sum of the individual displacements due to each one of the waves at that point at the same time.
if $y_1, y_2, y_3 \cdots \cdots$ are the displacements at a particular time at a particular position, due to individual waves, then the resultant displacement would be :
$$
y=y_1+y_2+y_3 \cdots
$$

Let at a given point two waves arrive with the phase difference $\phi$ and the equation of these waves are given by $y_1=a_1 \sin (\omega t), y_2=a_2 \sin (\omega t+\phi)$ then by principle of superposition
$$
y=y_1+y_2 \Longrightarrow A \sin (\omega t+\theta)
$$
Where $A=\sqrt{a_1^2+a_2^2+2 a_1 a_2 \cos (\phi)}$ and $\tan (\theta)=\frac{a_2 \sin \phi}{a_1+a_2 \cos (\phi)}$
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