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Oscillation Of Two Particle System - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • 3 Questions around this concept.

Solve by difficulty

A circular spring of natural length l_{0} is cut and welded with two beads of masses is cut and welded with two beads of masses m_{1} and m_{2} each such that the ratio of the original spring is k then find the frequency of oscillation of the heads in a smooth horizontal rigid tube. Assume m_{1}=m and m_{2}=3 m^{\prime}.

   

                         

Concepts Covered - 1

Oscillation of two particle system

Two blocks of masses m_{1}  and m_{2}  are connected with a spring of natural length l and spring constant k. The system is lying on a
frictionless horizontal surface. Initially, spring is compressed by a distance x_{0} as shown in the below Figure.

If we release these blocks from the compressed position, then they will oscillate and will perform SHM about their equilibrium position.

  • The time period of the blocks-

In this case, the reduced mass mr is given by  \frac{1}{m_{r}}=\frac{1}{m_{1}}+\frac{1}{m_{2}}

and T=2 \pi \sqrt{\frac{m_{r}}{k}}

Or 

  • The amplitude of the blocks-  Let the amplitude of the blocks as A1 and A2 

            then \ \ m_{1} A_{1}=m_{2} A_{2}

(As net external force is zero and initially the center of mass was at rest 

so \Delta x_{cm}=0 \\ )

           \begin{array}{l} \\ {\text { By energy conservation, } \frac{1}{2} k\left(A_{1}+A_{2}\right)^{2}=\frac{1}{2} k x \frac{1}{0}} \\ {\text { or, } A_{1}+A_{2}=x_{0} \quad \text { or, } \quad A_{1}+\frac{m_{1}}{m_{2}} a A_{1}=x_{0}} \\ {\text { or, } \quad \begin{aligned} A_{1}=& \frac{m_{2} x_{0}}{m_{1}+m_{2}} \\ \text { Similarly, } & A_{2}=\frac{m_{1} x_{0}}{m_{1}+m_{2}} \end{aligned}}\end{array}

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Oscillation of two particle system

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