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Composition Of Two SHM MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Composition of two SHM- part 2 is considered one the most difficult concept.

  • 29 Questions around this concept.

Solve by difficulty

Two waves are represented by the equations $\mathrm{y}_1=\mathrm{a} \sin (\omega t+\mathrm{kx}+0.57) \mathrm{m}$ and $\mathrm{y}_2=\mathrm{a} \cos (\omega t+\mathrm{kx}) \mathrm{m}$, where x is in meters and t is in s seconds. The phase difference between them is

The resultant of two rectangular simple harmonic motions of the same frequency and unequal amplitudes but differing in phase by $\ \frac {\pi}{2}$ is:

Concepts Covered - 2

Composition of two SHM: Part 1

Composition of two SHM:

If a particle is acted upon by two forces such that each force can produce SHM, then the resultant motion of the particle is a combination of SHM. 

Composition of two SHM in the same direction

Let a force $F_1$ produces an $S \mathrm{HM}$ of amplitude $A_1$ whose equation is given by

$$
x_1=A_1 \sin \omega t
$$


Let another force $F_2$ produce an SHM of amplitude $A_2$ whose equation is given by

$$
x_2=A \sin (\omega t+\phi)
$$


Now if force $F_1$ and $F_2$ is acted on the particle in the same direction then the resultant amplitude of the combination of SHM's is given by

$$
A=\sqrt{A_1^2+A_2^2+2 A_1 A_2 \cdot \cos \phi}
$$

$A_1$ and $A_2$ are the amplitude of two SHM's. $\phi_{\text {is }}$ phase difference.
Note: Here the frequency of each SHM's are the same
And the resulting phase is given by

$$
\phi^{\prime}=\tan ^{-1}\left(\frac{A_2 \sin \phi}{A_1+A_2 \cos \phi}\right)
$$
 

 

Composition of two SHM- part 2

Composition of SHM in perpendicular direction:

Let a force F1 on a particle produce an SHM given by 

$$
x=A \sin \omega t
$$

and a force $\mathrm{F}_2$ alone produces an SHM given by

$$
x=A \sin (\omega t+\phi)
$$

- Both the force $F_1$ and $F_2$ acting perpendicular on the particle will produce an SHM whose resultant is given by:

$$
\frac{x^2}{A_1{ }^2}+\frac{y_2^2}{A_2{ }^2}-\frac{2 x y \cos \phi}{A_1 A_2}=\sin ^2 \phi
$$
 

The above equation is the general equation of an ellipse. That is two forces acting perpendicular on a particle execute SHM along an elliptical path.

      

- When $\phi=0$ the resultant equation is given by

$$
y=\frac{A_2}{A_1} \cdot x
$$


It is a straight line with a slope
$\frac{A_2}{A_1}$ represented by the below figure

       

- When $\phi=\pi_{\text {resultant equation }}$

$$
y=\frac{-A_2}{A_1} \cdot x
$$

which is represented by below straight line with a slope $\frac{-A_2}{A_1}$

        

- When $\phi=\frac{\pi}{2}$ resultant equation

$$
\frac{x^2}{A_1{ }^2}+\frac{y^2}{A_2{ }^2}=1
$$


It represents a normal ellipse
- if
$A_1=A_2$ and $\phi=\frac{\pi}{2}$ then it represents a circle

Study it with Videos

Composition of two SHM: Part 1
Composition of two SHM- part 2

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Reference Books

Composition of two SHM: Part 1

Physics Part II Textbook for Class XI

Page No. : 33

Line : 66

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