Composition of two SHM- part 2 is considered one the most difficult concept.
29 Questions around this concept.
Two waves are represented by the equations $\mathrm{y}_1=\mathrm{a} \sin (\omega t+\mathrm{kx}+0.57) \mathrm{m}$ and $\mathrm{y}_2=\mathrm{a} \cos (\omega t+\mathrm{kx}) \mathrm{m}$, where x is in meters and t is in s seconds. The phase difference between them is
The resultant of two rectangular simple harmonic motions of the same frequency and unequal amplitudes but differing in phase by $\ \frac {\pi}{2}$ is:
Composition of two SHM:
If a particle is acted upon by two forces such that each force can produce SHM, then the resultant motion of the particle is a combination of SHM.
Composition of two SHM in the same direction
Let a force $F_1$ produces an $S \mathrm{HM}$ of amplitude $A_1$ whose equation is given by
$$
x_1=A_1 \sin \omega t
$$
Let another force $F_2$ produce an SHM of amplitude $A_2$ whose equation is given by
$$
x_2=A \sin (\omega t+\phi)
$$
Now if force $F_1$ and $F_2$ is acted on the particle in the same direction then the resultant amplitude of the combination of SHM's is given by
$$
A=\sqrt{A_1^2+A_2^2+2 A_1 A_2 \cdot \cos \phi}
$$
$A_1$ and $A_2$ are the amplitude of two SHM's. $\phi_{\text {is }}$ phase difference.
Note: Here the frequency of each SHM's are the same
And the resulting phase is given by
$$
\phi^{\prime}=\tan ^{-1}\left(\frac{A_2 \sin \phi}{A_1+A_2 \cos \phi}\right)
$$
Composition of SHM in perpendicular direction:
Let a force F1 on a particle produce an SHM given by
$$
x=A \sin \omega t
$$
and a force $\mathrm{F}_2$ alone produces an SHM given by
$$
x=A \sin (\omega t+\phi)
$$
- Both the force $F_1$ and $F_2$ acting perpendicular on the particle will produce an SHM whose resultant is given by:
$$
\frac{x^2}{A_1{ }^2}+\frac{y_2^2}{A_2{ }^2}-\frac{2 x y \cos \phi}{A_1 A_2}=\sin ^2 \phi
$$
The above equation is the general equation of an ellipse. That is two forces acting perpendicular on a particle execute SHM along an elliptical path.

- When $\phi=0$ the resultant equation is given by
$$
y=\frac{A_2}{A_1} \cdot x
$$
It is a straight line with a slope
$\frac{A_2}{A_1}$ represented by the below figure

- When $\phi=\pi_{\text {resultant equation }}$
$$
y=\frac{-A_2}{A_1} \cdot x
$$
which is represented by below straight line with a slope $\frac{-A_2}{A_1}$

- When $\phi=\frac{\pi}{2}$ resultant equation
$$
\frac{x^2}{A_1{ }^2}+\frac{y^2}{A_2{ }^2}=1
$$
It represents a normal ellipse
- if
$A_1=A_2$ and $\phi=\frac{\pi}{2}$ then it represents a circle
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