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Oxoacids of Phosphorus MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:24 PM | #NEET

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Which is the correct statement for the given acids?

Orthophosphoric acid is -

Which of the following statements is not valid for oxoacids of phosphorus?

Strong reducing behaviour of $\mathrm{H}_3 \mathrm{PO}_2$ is due to:

 The number of P−OH bonds and the oxidation state of phosphorus atom in pyrophosphoric acid (H4P2O7) respectively are :

The pair that contains two P-H bonds in each of the oxoacids is :

Oxidation number of P in $\mathrm{PO}_4^{3-}$, of S in $\mathrm{SO}_4^{2-}$ and that of $\mathrm{Cr}_2 \mathrm{O}_7^{2-}$ are respectively

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Assertion: Hypophosphorous acid is a strong reducing agent.

Reason: Hypophosphorous acid can donate $\mathrm{H}^{+}$ ions, leading to the formation of hypophosphite ions, which have a strong reducing ability.
 

Among the following molecules, which contains the maximum number of P-H bonds? 

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How many bridging oxygen atoms are present in $P_4 O_{10}$?

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Oxoacids of Phosphorus

Phosphorus forms a number of oxoacids. The important oxoacids of phosphorus with their formulas, methods of preparation and the presence of some characteristic bonds in their structures are given in Table given below.

The compositions of the oxoacids are interrelated in terms of loss or gain of H2O molecule or O-atom. The structures of some important oxoacids are given in later pictures. In oxoacids phosphorus is tetrahedrally surrounded by other atoms. All these acids contain at least one P=O bond and one P–OH bond. The oxoacids in which phosphorus has lower oxidation state (less than +5) contain, in addition to P=O and P–OH bonds, either P–P (e.g., in H4P2O6) or P–H (e.g., in H3PO2) bonds but not both. These acids in +3 oxidation state of phosphorus tend to disproportionate to higher and lower oxidation states. For example, orthophophorous acid (or phosphorous acid) on heating disproportionates to give orthophosphoric acid (or phosphoric acid) and phosphine.

4 \mathrm{H}_{3} \mathrm{PO}_{3} \rightarrow 3 \mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{PH}_{3}

    

  

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