13 Questions around this concept.
When an electric dipole $\vec{p}$ is placed in a uniform electric field $\vec{E}$ then at what angle between $\vec{p}$ and $\vec{E}$ the value of torque will be maximum
A molecule with a dipole moment p is placed in an electric field of strength E. Initially the dipole is aligned parallel to the field. If the dipole is to be rotated to be anti-parallel to the field, the work required to be done by an external agency is
An electric dipole of moment 'p' is placed in an electric field of intensity 'E'. The dipole acquires a position such that the axis of the dipole makes an angle with the direction of the field. Assuming that the potential energy of the dipole to be zero when
= 90°, the torque and the potential energy of the dipole will respectively be:
When a dipole is kept in a uniform electric field. The net force experienced by the dipole is zero as shown in the below figure.
I.e $F_{n e t}=0$

But it will experience torque. And Net torque about the center of dipole is given as
$
\tau=Q E d \sin \theta \text { or } \tau=P E \sin \theta \text { or } \vec{\tau}=\vec{P} \times \vec{E}
$
Work done in rotation-
Work done in rotation-

Then work done by electric force for rotating a dipole through an angle $\theta_2$ from the equilibrium position of an angle $\theta_1$ (As shown in the above figure) is given as
$
\begin{aligned}
& W_{\text {ele }}=\int \tau d \theta=\int_{\theta_1}^{\theta_2} \tau d \theta \cos \left(180^0\right)=-\int_{\theta_1}^{\theta_2} \tau d \theta \\
& \Rightarrow W_{\text {ele }}=-\int_{\theta_1}^{\theta_2}(P \times E) d \theta=-\int_{\theta_1}^{\theta_2}(P E \operatorname{Sin} \theta) d \theta=P E\left(\cos \Theta_2-\cos \Theta_1\right)
\end{aligned}
$
And So work done by an external force is $W=P E\left(\cos \Theta_1-\cos \Theta_2\right)$
For example
$
\begin{aligned}
& \text { if } \Theta_1=0^{\circ} \text { and } \Theta_2=\Theta \\
& W=P E(1-\cos \Theta) \\
& \text { if } \Theta_1=90^{\circ} \text { and } \Theta_2=\Theta \\
& W=-P E \cos \Theta
\end{aligned}
$
Potential Energy of a dipole kept in Electric field-
$
\text { As } \Delta U=-W_{\text {ele }}=W
$
So change in Potential Energy of a dipole when it is rotated through an angle $\theta_2$ from the equilibrium position of an angle $\theta_1$ is given as $\Delta U=P E\left(\cos \Theta_1-\cos \Theta_2\right)$
$
\begin{aligned}
& \text { if } \Theta_1=90^{\circ} \text { and } \Theta_2=\Theta \\
& \Delta U=U_{\theta_2}-U_{\theta_1}=U_\theta-U_{90}=-P E \cos \Theta
\end{aligned}
$
Assuming $\Theta_1=90^{\circ}$ and $U_{90^{\circ}}=0$
we can write $U=U_\theta=-\vec{P} \cdot \vec{E}$
Equilibrium of Dipole-
1. Stable Equilibrium-
$
\begin{aligned}
& \Theta=0^{\circ} \\
& \tau=0 \\
& U_{\min }=-P E
\end{aligned}
$

2. Unstable Equilibrium-
$\begin{aligned} & \Theta=180^{\circ} \\ & \tau=0 \\ & U_{\max }=P E\end{aligned}$

3. Not in equilibrium-
$\begin{aligned} & \Theta=90^{\circ} \\ & \tau_{\max }=P E \\ & U=0\end{aligned}$

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