ALLEN NEET Coaching
ApplyAce your NEET preparation with ALLEN Online Programs
12 Questions around this concept.
In this concept we are going to derive the electric field due to continous charge on a ring -
In this one should notice that there symmetry in this situation. Every element dq can be paired with a similar element on the opposite side of the ring. Every component perpendicular to the x-axis is thus cancelled by a component in the opposite direction.
In the summation process, all the perpendicular components add to zero. Thus we only add the components, which all lie along the +X direction, and this is a simple scalar integral. From Coulomb’s Law in vector form,
As we integrate around the ring, all the terms remain constant
Also,
So, the Net electric field is -
Graph between E and X -
If,
,
"Stay in the loop. Receive exam news, study resources, and expert advice!"