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Sonometer MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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Fundamental frequency of sonometer wire is n. If the tension is made thee times and length and diameter are also increased by 3 times, what is the new frequency

If the tension and diameter of a sonometer wire of fundamental frequency n are doubled, and the density is halved, then its fundamental frequency will become:

When the string of a sonometer of length L between bridges vibrates in the second overtone, the amplitude of vibration is maximum at:

Concepts Covered - 1

Sonometer

Sonometer - 

It is a device used to measure the velocity of the transverse mechanical wave in a stretched metal wire.

The principle of sonometer is based on the resonance of string vibrations. Working oscillations are induced in a clamped string by an external source like a tuning fork or an oscillator and because of this, the amplitude becomes very high when resonance takes place. 

There are two figures given below which show the setup of the Sonometer. There is a wooden box M on which wire AB is stretched by weight as shown in Figure (a). There are two clamps C1 and C2 which are ready to slide to change the length of the wire between the clamps. 

Now we are placing an oscillating tuning fork in contact with the sonometer wire (See Figure (b)). When they get in touch, some oscillations are transferred to the wire. Let the tension in the wire be T and $\mu$ is the mass per unit length of the wire. Also, $n_0$ is the frequency of the tuning fork, then the wavelength of the wave in the wire is -

$$
\lambda=\frac{v}{n_0}=\frac{1}{n_0} \sqrt{\frac{T}{\mu}}
$$
 

                                                                                      

If the length between clamps is an integral multiple of $\lambda / 2$ then stationary waves are established in the portion of wire between $C_{1 \text { and }} C_2$. To do this, the Clamp $C_1$ is fixed and $C_2$ is displaced so that the oscillation amplitude of the wire is increasing and stationary waves are established. Let in this situation the length between clamps is $l$, now again $C_2$ is displaced away from $C_{1 \text { so that resonance is obtained. This }}$ will happen again when the clamp reaches the position $C_3$ and when the next node of stationary waves is present. Let this length be $l_{\text {, if }} l_1$ and $l_2$ are two successive resonance lengths then we can write -

$$
\begin{gathered}
l_2-l_1=\frac{\lambda}{2} \\
\text { so }^2 \lambda=2\left(l_2-l_1\right)
\end{gathered}
$$


If $n_0$ is the frequency of oscillation, then the velocity of the string wave in wire-

$$
\begin{aligned}
v & =n_0 \lambda \\
& =2 n_0\left(l_2-l_1\right)
\end{aligned}
$$


This is partially measured velocity and we can compare this velocity with the formula

$$
\sqrt{\frac{T}{\mu}}
$$
 

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