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    Preparation of Alkenes MCQ - NEET Practice Questions with Answers

    Edited By admin | Updated on Sep 25, 2023 25:24 PM | #NEET

    Quick Facts

    • Reduction of Alkynes to Alkenes, Dehalogenation of Vicinal Halides is considered one of the most asked concept.

    • 52 Questions around this concept.

    Solve by difficulty

    Conversion of alkyne to cis-alkene can be achieved using the reagent

    2–Hexyne gives trans–2–Hexene on treatment with :

    Which of the following is not the product of dehydration of ?

    The main product of the following reaction is

     

    Elimination of bromine from 2­-bromobutane results in the formation of

    Which of the following compounds will undergo racemisation when solutions when solutions of KOH hydrolyses?

    Concepts Covered - 8

    Reduction of Alkynes to Alkenes

    Alkynes on partial reduction with calculated amount of dihydrogen in the presence of palladised charcoal partially deactivated with poisons like sulphur compounds or quinoline give alkenes. Partially deactivated palladised charcoal is known as Lindlar’s catalyst. Alkenes thus obtained are having cis geometry. However, alkynes on reduction with sodium in liquid ammonia form trans alkenes.

    Dehydration of Alcohol by Conc. H2SO4

    When alcohols are heated with dehydrating agents like H2SO4 170oC, H3PO4 200oC, ZnCl2 350oC, BF3, dry HCl, KHSO4 etc alkenes are formed as follows:


    It involves carbocation formation followed by H- or R- or Ring expansion to get more stable carbocation to get the major product.

    Some examples include:

    Saytzeff's and Hoffmann Rule, Dehydration by Al2O3 and ThO2

    Saytzeff's rule
    This rule states that in dehydrohalogenation reactions, the preferred product is always that alkene which is most stable or in other words which has more number of \alpha-hydrogen atoms.

    Hoffmann's rule
    This rule states that the alkene formed would be the least stable as the major product or in other words that alkene would be formed which has the least number of \alpha-hydrogen atoms.

    Dehydration by Al2O3
    Since the reagent used is Al2O3, thus the Saytzeff's rule will be applied and E2 elimination will take place and no carbocation will form. When ethanol is passed over heated aluminium oxide then ethene is formed as the final product. The reaction occurs as follows:

    \mathrm{CH_{3}-CH_{2}-OH\: \overset{Al_{2}O_{3}}{\longrightarrow}\: CH_{2}=CH_{2}\: +\: H_{2}O}

    Dehydration by ThO2
    Since the reagent used is ThO2, thus the Hoffmann's rule will be applied and E2 elimination will take place and no carbocation will form. The reaction occurs as follows:

    \mathrm{CH_{3}-CH_{2}-CH-OH-CH_{3}\: \overset{ThO_{2}}{\longrightarrow}\: CH_{3}-CH_{2}-CH=CH_{2}}

    Dehydrohalogenation of Alkyl Halides

    When alkyl halides are heated with reagents like C2H5O-, alc. KOH, NaNH2, KNH2, (Me)3COK etc. then alkenes are formed as the product. The general reaction occurs as follows:

    Mechanism

    Some examples include:

    (1)
     

    (2) 

    Dehalogenation of Vicinal Halides

    When vicinal dihalides are heated with Zn dust or NaI/Acetone, alkene having the same number of carbon is obtained. This reaction is known as dehalogenation. The reaction occurs as follows:

    Mechanism

    For example:

    Wittig's Reaction

    In this reaction, methylene triphenyl phosphorane or phosphorous ylide is treated with a carbonyl compound to prepare an alkene. There are two important components of this reaction:

    • A carbonyl compound
    • A species known as "ylide". The "ylide" is a species with opposite charges on adjacent atoms.

    This reaction is named after George Wittig who was awarded the Nobel prize for this work in 1979. A principal advantage of alkene synthesis by the Wittig reaction is that the location of the double bond is absolutely fixed, in contrast to the mixtures often produced by alcohol dehydration.

    Mechanism

    For example:

    Pyrolysis of Quaternary Ammonium Salts

    Pyrolysis of quaternary ammonium salts follows the Hoffmann elimination. This means the less stable alkene will form. In this reaction, an amine reacts with 3 moles of methyl iodide and forms quaternary ammonium salt. Now heating this salt with moist Ag2O or AgOH will form alkene.

    The reaction occurs as follows:

    \mathrm{R-CH_{2}-CH_{2}-NH_{2}\:\overset{CH_{3}I}{\longrightarrow}R-CH_{2}-CH_{2}-NH-CH_{3}\: +\: HI\: \overset{CH_{3}I}{\longrightarrow}R-CH_{2}-CH_{2}-N-(CH_{3})_{2}\: +\: HI}

    \mathrm{\overset{CH_{3}I}{\longrightarrow}\: R-CH_{2}-CH_{2}-N^{+}-(CH_{3})_{3}\: \xrightarrow[AgOH]{Moist\: Ag_{2}O\: or}\: R-CH=CH_{2}\: +\: N-(CH_{3})_{3}}

    Cope's Reaction, Pyrolysis of Ester

    Cope's reaction
    When a tertiary amine oxide bearing one or more beta hydrogens is heated, it is converted to an alkene. The reaction is known as Cope elimination or Cope reaction. The net reaction is 1,2-elimination hence the name Cope elimination.

    For example:

    Pyrolysis of Esters
    When esters are heated in presence of liquid N2 and glass wool, then alkyl part of ester converts into respective alkene while alkanoate part of ester converts into respective acid.

    For example:

    Study it with Videos

    Reduction of Alkynes to Alkenes
    Dehydration of Alcohol by Conc. H2SO4
    Saytzeff's and Hoffmann Rule, Dehydration by Al2O3 and ThO2

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    Books

    Reference Books

    Reduction of Alkynes to Alkenes

    Chemistry Part II Textbook for Class XI

    Page No. : 387

    Line : 9

    Dehydration of Alcohol by Conc. H2SO4

    Chemistry Part II Textbook for Class XI

    Page No. : 388

    Line : 30

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