Relationship Between Linear And Angular Motion MCQ

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	Linear Motion	Rotational Motion
I	If linear acceleration =a=0 Then u = constant and s = u t.Í	If angular acceleration $=\alpha=0$ Then $\omega=$ constant and $\theta=\omega \cdot t$
II	If linear acceleration= a = constant 1. $a=\frac{v-u}{t}$ 2. $v=u+a t$ 3. $s=u t+\frac{1}{2} a t^2$ 4. $s=\frac{v+u}{2} * t$ 5. $v^2-u^2=2 a s$ 6.$ S_n=u+\frac{a}{2}(2 n-1) $	If angular acceleration=$\alpha=$ constant $\begin{aligned} & \text { 1. } \alpha=\frac{\omega_f-\omega_i}{t} \\ & \text { 2. } \omega_f=\omega_i+\alpha \cdot t \\ & \text { 3. } \theta=\omega_i \cdot t+\frac{1}{2} \cdot \alpha \cdot t^2 \\ & \text { 4. } \theta=\frac{\omega_f+\omega_i}{2} * t \\ & \text { 5. } \omega_f^2-\omega_i^2=2 \alpha \theta \\ & \text { 5. } \theta_n=\omega_i+\frac{\alpha}{2}(2 n-1)\end{aligned}$
III	If linear acceleration= a Not equal to constant 1. $v=\frac{d x}{d t}$ 2. $a=\frac{d v}{d t}=\frac{d^2 x}{d t^2}$ 3. $v \cdot d v=a . d s$	If angular acceleration $=\alpha \neq$ constant $$ \begin{aligned} & \text { 1. } \omega=\frac{d \theta}{d t} \\ & { }_{2 .}=\frac{d \omega}{d t}=\frac{d^2 \theta}{d t^2} \\ & \text { 3. } \omega \cdot d \omega=\alpha \cdot d \theta \end{aligned} $$

Relationship Between Linear And Angular Motion MCQ - Practice Questions with Answers