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Centre Of Mass Of Semicircular Ring - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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Position of centre of mass for semicircular ring

Have a look at the figure of semicircular ring.

 

Since it is symmetrical about y-axis on both sides of the origin

So we can say that  its x_{cm} = 0

And its z_{cm} = 0 as  z-coordinate is zero for all particles of semicircular ring.

Now, we will calculate its y_{cm} which is given by

y_{cm} = \frac{\int y.dm}{\int dm}

So , Take a small elemental arc of mass dm at an angle \theta  from the x-direction.

Its angular width d 

If the radius of the ring is R then its y coordinate will be Rsin

So,  dm=\frac{M}{\pi R}*Rd\theta =\frac{M}{\pi }d\theta

As,  y_{cm} = \frac{\int y.dm}{\int dm}

So, y_{cm}=\frac{\int_{\pi }^{0}\frac{M}{\pi R}*R*Rsin\theta d\theta}{M}=\frac{R}{\pi }\int_{\pi }^{0}sin\theta d\theta=\frac{2R}{\pi }

 

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Position of centre of mass for semicircular ring

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