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Equation Of Path Of A Projectile MCQ - Practice Questions with Answers
Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET
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13 Questions around this concept.
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A particle just clears a wall of height b at a distance a and strikes the ground at a distance c from the point of projection. The angle of projection is
An object is projected with a velocity of making an angle of
with horizontal The equation for the trajectory is
is height
is horizontal distance,
and
are constant, the ratio
is
A body of mass is being Projected with an angle of
with the vertical. The trajectory of body is observed at point (30,20) If the '
', is time of fight Then its momentum vector, at time
is
NEET 2025: Syllabus | Most Scoring concepts | NEET PYQ's (2015-24)
If the initial velocity in the Horizontal direction of a projectile is unit vector and the equation of trajectory is
. Find the
-component vector of initial velocity
Concepts Covered - 1
Equation of path of a projectile
$$
y=x \tan \theta-\frac{g x^2}{2 u^2 \cos ^2 \theta}
$$
It is equation of parabola, So the trajectory/path of the projectile is parabolic in nature.
$g \rightarrow$ Acceleration due to gravity
$u \rightarrow$ initial velocity
$\theta=$ Angle of projection
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