7 Questions around this concept.
An object is kept at 40 cm from a concave mirror of a focal length 20 cm. If the object start moving perpendicular to the principle axis with 6 cm/s then the velocity of the image is :
The velocity of a point is $v_0=2 \mathrm{~cm} / \mathrm{s}$ when it is placed at a distance of 30 cm from a lens moving with a speed $v_{\text {lens }}=2 \mathrm{~cm} / \mathrm{s}$ towards left. If the focal length of the lens is $f=20 \mathrm{~cm}$, find the velocity of the image.

A plane mirror is placed at origin parallel to y-axis facing the positive x-axis. An object starts from (2,0 ,0) with a velocity $(2 \hat{i}+2 \hat{j})$ m/s. The relative velocity of the image with respect to object is along:
A point object is located at a distance of 100 m from a screen. A lens of focal length 23 cm mounted on a movable frictionless stand is kept between the source and the screen. The stand is attached to a spring of natural length 50cm and spring constant 800 N/m as shown. The mass of the stand with the lens is 2 kg. How much impulse P should be imparted to the stand so that a real image of the object is formed on the screen after a fixed time gap? (Neglect the width of the stand).

A man rowing his boat to cover a certain distance ‘X’. If the time taken by the man to cover the distance in upstream is 6 hours more than the time taken to cover the distance by the same boat in downstream. The speed of the stream is $37\frac {1}{2}\%$ of the speed of the boat in still water. If the man covers 110 km distance in downstream in 10 hours by the same boat, then find the value of ‘X’.
Relation between object and image velocity in lens -
Case 1 : When object is moving along the principal axis -

As we have learned the following equation -
After differentiation -
Case 2 : When object is moving perpendicular to the principal axis -

After differntiation -
Here, m = magnification,
v = Position of image
u = Position of object
= Velocity vector
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