5 Questions around this concept.
A plane mirror is placed at origin parallel to y-axis facing the positive x-axis. An object starts from (2,0 ,0) with a velocity $(2 \hat{i}+2 \hat{j})$ m/s. The relative velocity of the image with respect to object is along:
An object and a plane mirror are shown in the figure. The mirror is moved with velocity.
V as shown. The velocity of the image is :
A hemispherical paper-weight contains a small artificial flower of transverse size 2mm on its axis of symmetry at a distance of 4cm from its flat surface. What is the size of the flower as it appears to an observer when he looks at it along the axis of symmetry from the top? (The radius of the hemisphere is 10cm. Index of refraction of glass = 1.5).

The relation between the velocity of the object and mirror in-plane mirror:
In case of plane mirror, distance of the object from the mirror is equal to distance of image from the mirror.
i.e Distance of Image formed in the mirror is same as the distance of the object formed the surface of the mirror.

Hence, from the mirror property:
$$
x_{\mathrm{im}}=-x_{\mathrm{on}}, y_{\mathrm{im}}=y_{\mathrm{om}} \text { and } z_{\mathrm{im}}=z_{\mathrm{om}}
$$
Here $x_{i m}$ means " x coordinate of image with respect to mirror.
Differentiating w.r.t time, we get,
$$
v_{(\mathrm{im}) x}=-v_{(\mathrm{om}) x} ; \quad v_{(\mathrm{im}) y}=v_{(\mathrm{om}) y} ; \quad v_{(\mathrm{im}) \mathrm{z}}=v_{(\mathrm{orn}) z}
$$
Here,
$v_i=$ velocity of the image with respect to the ground.
$v_0=$ velocity of the object with respect to the ground.
$v_{o m}=$ velocity of the object with respect to the mirror.
$v_{i m}=$ velocity of the object with respect to the mirror.
i.e $\vec{v}_{\text {om }}=\vec{v}_{\mathrm{o}}-\vec{v}_{\mathrm{m}} \quad$ and $\quad \vec{v}_{\mathrm{im}}=\vec{v}_{\mathrm{i}}-\vec{v}_{\mathrm{m}}$
For x -axis-
$$
\begin{aligned}
& v_{(i m) x}=-v_{(\mathrm{om}) x} \\
& \Rightarrow \quad v_i-v_{\mathrm{m}}=-\left(v_{\mathrm{o}}-v_{\mathrm{m}}\right) \quad(\text { for } x \text {-axis })
\end{aligned}
$$
- I.e When the object moves with speed $v$ towards (or away)
also moves toward (or away) with speed $v$. But the relative speed of image w.r.t. the object is $2 v$.
For y -axis and z -axis
$$
v_{(\mathrm{im}) y}=v_{(\mathrm{om}) y} ; \quad v_{(\mathrm{im}) \mathrm{z}}=v_{(\mathrm{om}) z}
$$
| Relative velocity of image w.r.t. mirror | = | Relative velocity of object w.r.t. mirror |
But $v_1-v_{\mathrm{m}}=\left(v_{\mathrm{o}}-v_{\mathrm{m}}\right)$
or $\quad v_{\mathrm{i}}=v_{\mathrm{o}}$
for $y$-and $z$-axis.
Here, $v_i=$ velocity of the image with respect to the ground.
$v_0=$ velocity of the object with respect to the ground.
i.e Velocity of the object is equal to the velocity of the image when the object is moving to parallel to the mirror surface.
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