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Adiabatic Process MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

Adiabatic Reversible And Irreversible Expansion is considered one of the most asked concept.
7 Questions around this concept.

Solve by difficulty

EASY

Which of the following is correct option for free expansion of an ideal gas under adiabatic condition ?

$q=0,\:\Delta T\neq 0,w=0$

$q\neq0,\:\Delta T= 0,w=0$

$q=0,\:\Delta T= 0,w=0$

$q=0,\:\Delta T< 0,w\neq0$

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Concepts Covered - 1

Adiabatic Reversible And Irreversible Expansion

Adiabatic Reversible Expansion of An Ideal Gas

(1) Process Equations for Reversible Adiabatic Process

$\mathrm{PV^\gamma = constant}$

$\mathrm{TV^{\gamma-1} = constant}$

$\mathrm{T^\gamma\ P^{1-\gamma} = constant}$

As in an adiabatic change, there is no transfer of heat that is, q = 0 or dq = 0.

$\\ \mathrm{ \Delta E=W } \\\mathrm{ d E=d W}$

W can be written as

$W= \Delta E= nC_V \Delta T=n\frac{R}{\gamma-1} \Delta T=\frac{P_2 V_2-P_1 V_1}{\gamma - 1}\longrightarrow(1)$

Alternatively, the Work can also be derived by the formula

$\mathrm{W= \int P_{ext}\ dV\ and\ PV^\gamma = constant}$

(2)Irreversible Adiabatic Process

The process equations mentioned above for the Reversible Adiabatic Process do not hold for the Irreversible Adiabatic Process.

However, the First law of Thermodynamics and the Ideal Gas equation hold true for the Irreversible Adiabatic Process and the work can be calculated using the Equation (1) as given above

(3)Irreversible Adiabatic Free Expansion

In a free expansion, the expansion is carried out against Vacuum in an isolated container. Thus, the value of external pressure is zero so work done is zero and also Q is zero as the system is Isolated ( Adiabatic).

Thus, it can be said that

$\begin{array}{l}{\mathrm{ \Delta E=W=0}} \\ {\mathrm{ \Delta T=0, \Delta H=0}}\end{array}$