Centripetal Force For Non-uniform Circular Motion MCQ - Practice Questions with Answers

$\begin{aligned} & F_c=m a_c=\frac{m v^2}{r} \quad\left(\vec{F}_c \perp \vec{v}\right) \\ & \mathrm{F}_{\mathrm{t}}=\mathrm{ma} \mathrm{a}_{\mathrm{t}} \\ & F_{n e t}=m \sqrt{a_c^2+a_t^2} \\ & \mathrm{~m}=\text { mass } \\ & \mathrm{a}_{\mathrm{c}}=\text { centripetal acceleration } \\ & \mathrm{a}_{\mathrm{t}}=\text { tangential acceleration } \\ & \mathrm{F}_{\mathrm{c}}=\text { centripetal farce }\end{aligned}$