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Newton’s Second and Third Law of motion is considered one the most difficult concept.
46 Questions around this concept.
A machine gun fires a bullet of mass of 40g with a velocity of 1200 ms-1 The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
When forces F1, F2, and F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary If the force F1 is now removed then the acceleration of the particle is :
A particle of mass m is at rest at the origin at time $\mathrm{t}=0$. It is subjected to a force $F(t)=F_0 e^{-b t}$ in the x direction Its speed $v(t)$ is depicted by which of the following curves ?
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A man of 60 kg is running on the road and suddenly jumps into a stationary trolly car of mass 120 kg . Then, the trolly car starts moving with velocity $2 \mathrm{~ms}^{-1}$. The velocity of the running man was _______ $\qquad$ $\mathrm{ms}^{-1}$, when he jumps into the car.
The mass of a lift is 2,000 kg. When the tension in the supporting cable is 28000N, then its acceleration is:
A bullet fired into a fixed target loses half its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ? (in cm)
The figure shows the position-time $(x-t)$ graph of one-dimensional motion of a body of mass 0.4 kg. The magnitude of each impulse (in N-s) is
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A book exerts a force of 2N downwards, into a chair that exerts a force of 5N downwards to the floor it stands on. What is the force (in N) that the floor exerts upwards on the chair?
Newton’s second law of motion:-
It states that the acceleration of the particle measured from an inertial frame is given by the (vector) sum of all the forces acting on the particle divided by its mass (only when mass is constant), i.e.,
$\vec{a}=\frac{\vec{F}}{m} \Rightarrow \vec{F}=m \vec{a}$
Impulse:
The quantity $\vec{I}=\int_{t_1}^{t_2} \vec{F} \cdot d t$ is known as the impulse of the force F during the time interval $\mathrm{t}_1$ to $\mathrm{t}_2$ and
Is equal to the change in the momentum of the body on which it acts,
$$
P_f-P_1=\int_{P_1}^{P_1} d P=\int \frac{d P}{d t} * d t=\int F d t \Rightarrow \text { Area under force and }
$$
time graph is an impulse.
2. Dimension- MLT-1
3. Unit- kg-m/sec
Impulse Momentum Theorem- Newton’s 2nd law can also be written as:
Rate of change in momentum = Force Applied
$\vec{F}=\frac{d \vec{p}}{d t}$
2. Newton’s third law of motion:-
It states that "If a body A exerts a force F on another body B, then B exerts a force (-F) on A."
Action and reaction never act on the same bodies.
3. Law of Conservation of Linear Momentum:
As we know, $\vec{F}=\frac{d \vec{p}}{d t}$, If F=0 then changes in momentum=0 ⇒p=constant.
ஃ p=p1+p2+p3+......=constant
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