Acceleration of Block on Smooth Inclined Plane is considered one of the most asked concept.
17 Questions around this concept.
Two fixed frictionless inclined planes making an angle 30° and 60° with the vertical are shown in the figure. Two blocks A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B?

In the figure shown the acceleration of A is $\vec{a}_A=15 i+15 j$ then the acceleration of $B$ is: (A remains in contact with B)
For no friction to act on a block kept on an accelerating wedge as shown in figure, acceleration of the wedge should be

When an Inclined Plane is at rest

$R=m g \cos \theta$ along with normal to the incline $m g \sin \theta=m a_{\text {along the incline }}$
$$
a=g \sin \theta
$$
When an Inclined Plane is given Acceleration 'b'

$$
\begin{aligned}
& R=m g \cos \theta+m b \sin \theta \\
& m a=m g \sin \theta-m b \cos \theta \\
& a=g \sin \theta-b \cos \theta
\end{aligned}
$$
* Condition for the body to be at rest relative to the inclined plane.
$$
\begin{aligned}
& a=g \sin \theta-b \cos \theta=0 \\
& b=g \tan \theta
\end{aligned}
$$
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