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7 Questions around this concept.
A ball of mass $0.20 kg$ hits a wall at an angle of $45^{\circ}$ with a velocity of $25 \mathrm{~m} / \mathrm{s}$. If the ball rebounds at $90^{\circ}$ to the direction of incidence with the same speed. Calculate the magnitude of change in momentum of the ball.
A ball is thrown vertically up (taken as + z-axis) from the ground . The correct momentum -height (p-h) diagram is :
A bullet of mass 10 g moving horizontal with a velocity of 400 m s-1 strikes a wood block of mass 2 kg which is suspended by light inextensible string of length 5 m. As result, the centre of gravity of the block found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be
NEET 2025: Syllabus | Most Scoring concepts | NEET PYQ's (2015-24)
A stone is dropped from a height of h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by:
Linear momentum of a body is the quantity of motion contained in the body.
It is measured in terms of the force required to stop the body in unit time.
If a body of mass m is moving with velocity v, then its linear momentum p is given by p=mv.
It is a vector quantity and its direction is the same as the direction of the velocity of the body.
S.I. Unit : kg-m/sec
Dimension- MLT-1
If two objects of different masses have the same momentum, the lighter body possesses greater velocity.
As p=m1v1=m2v2=constant
$\therefore \frac{V_1}{V_2}=\frac{m_2}{m_1} \Rightarrow V \alpha \frac{1}{m}$
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