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Characteristic X-rays - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Characteristic X-Rays is considered one of the most asked concept.

  • 17 Questions around this concept.

Solve by difficulty

The wave length of the characteristic X-ray \mathrm{K}_\alpha line emitted by a hydrogen like atom is 0.32 \AA. The wave length of \mathrm{K}_\beta line emitted by the same element is:

what element has k_{\alpha } line of wavelength 1.785 A? R=1099737 \: cm^{-1}

The wavelength K_{\alpha } of X-rays for two metals ‘A’ and ‘B’ are \frac{4}{1875}R  and \frac{1}{675}R respectively , where ‘R’ is Rydberg constant. Find the number of elements lying between A and B according to their atomic numbers

The differential scattering cross section is given by \mathrm{D(\theta)=a^2+b^2 \cos ^2 \theta} if the intensity of incoming particle is I what will be intensity of scatteried particle.

The wave length of the characteristic \mathrm{ \mathrm{X}-ray \mathrm{K}_\alpha} line emitted by a hydrogen like atom is \mathrm{ 0.32 \AA}. The wave length of \mathrm{\mathrm{K}_\beta} line emitted by the same element is:




 

The intensity of X-rays from a Coolidge tube is plotted against wavelength \lambda as shown in the figure. The minimum wavelength found is \lambda_C and the wavelength of the \mathrm{K_\alpha} line is \mathrm{\lambda_{\mathrm{K}}}. As the accelerating voltage is increased
 

\mathrm{K}_\alpha wavelength emitted by an atom \lambda is given by an atom of atomic number \mathrm{Z=11} is \lambda. Find the atomic number for an atom that emits \mathrm{K}_\alpha radiation with wavelength 4 \lambda.
 

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For x-rays coming from a Coolidge tube, consider the following statements:

A. product of cutoff wavelength and accelerating voltage is a constant

B. \lambda\left(\mathrm{K}_\alpha\right) is smaller than \lambda\left(\mathrm{K}_\beta\right)
 

The \mathrm{K} \alpha \mathrm{x}-ray emission line of tungsten occurs at \mathrm{\lambda=0.021 \mathrm{~nm}}. The energy difference between \mathrm{\mathrm{K}\: and \: \mathrm{L}} levels in this atoms is about :
 

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Stopping potentials of 24,100,110,115 \mathrm{kV} are measured for photoelectrons emitted from a certain element when it is irradiated with monochromatic \mathrm{X}-rays. The element is used as a target in an \mathrm{X}-ray tube. The energy of \mathrm{\mathrm{K}_\alpha} line is -


 

Concepts Covered - 1

Characteristic X-Rays

Characteristic X-Rays -

Few of the fast moving electrons having high velocity penetrate the surface atoms of the target material and knock out the tightly bound electrons even from the inner most shells of the atom. Now when the electron is knocked out, a vacancy is created at that place. To fill this vacancy electrons from higher shells jump to fill the created vacancies, we know that when an electron jumps from a higher energy orbit E1  to lower energy orbit  E2 , it radiates energy  (E1−E2). Thus this energy difference is radiated in the form of X-rays of very small but definite wavelength which depends upon the target material. The X-ray spectrum consists of sharp lines and is called characteristic X-ray spectrum. These X-rays are called characteristic X-rays because they are characteristic of the element used as target anode. Characteristic X-rays have a line spectral distribution unlike the continuous X-rays. The wavelength spectrum of the X-frequencies orresponding to these lines are the characteristic of the material or the target, i.e., anode material.

                                                                 

When the atoms of the target material are bombarded with high energy electrons (or hard X-rays), which possess enough energy to penetrate into the atom, they knockout the electron of inner shell (say K shell, n=1 ). When an electron is missing in the K shell, an electron from next upper shell makes a quantum jump to fill the vacancy in the K shell. In the transition process, the electron radiates
energy whose frequency lies in the X-ray region. The frequency of emitted radiation (i.e., of photon) is given by - 

                                                                                     v=R Z_{e}^{2}\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right)

                                     

 

Another vacancy is now created in the L shell which is again filled up by another electron jump from one of the upper shell M which results in the emission of another photon, but of different X-ray frequency. This transition continues till outer shells are reached, thus, resulting in the continues till outer shells are reached, thus, resulting in the emission of series of spectral lines. The transitions of electrons from various outer shells to the inner most K shell produces a group of X-ray lines called as K -series. These radiations are most energetic and most penetrating. K-series is further divided into K_{\alpha}, K_{\beta}, K_{\gamma}, \ldots depending upon the outer shell from which the transition is made (see figure).

 

                                                                 

Similarly the rest of the series can be shown as below -


                                         

Now notice the graph shown below and the sharp peaks obtained in graph are known as characteristic X-rays because they are characteristic of the target material. The characteristic wavelengths of the material having atomic number Z are called characteristic X-rays and the spectrum obtained is called characteristic spectrum. If a target material of atomic number Z^{\prime} is used, then peaks are shifted. 

                                                              

The characteristic wavelengths of the material having atomic number Z are called characteristic X-rays and the spectrum
obtained is called characteristic spectrum. If a target material of atomic number Z^{\prime} is used, then peaks are shifted as shown below -

                                                             

 

X - ray absorption-

The intensity of X-rays at any point may be defined as the energy falling per second per unit area held perpendicular to the direction of energy flow. Let I_{0} be the intensity of incident beam and I be the intensity of beam after penetrating a thickness x of a material, then I=I_{0} e^{-m x}, where m is the coefficient of absorption or absorption coefficient of the material. The absorption coefficient depends upon wavelength of X-rays, density of material, and atomic number of material. The elements of high atomic mass and high density absorb X-rays to a higher degree.

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Characteristic X-Rays

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