7 Questions around this concept.
Consider the following reaction,
ethanol $\xrightarrow{\mathrm{PBr}} \mathrm{X} \xrightarrow{\text { alc. } \mathrm{KOH}} \mathrm{Y} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}, \text { heat }]{\text { (i) } \mathrm{H}_2 \mathrm{SO}_4 \text { room temperature }} \mathrm{Z}$
the product Z is:
The relation between Ka,Kb and Kw can be understand by the following reaction.
Base Conjugate acid
The equilibrium constant Kb for base NH3 is given as:
Again, the reaction is:
The equilibrium constant Ka for conjugate acid NH4+ is given as:
Thus, Ka x Kb = [H3O+][OH-] = Kw
Thus, Ka ∝ 1/Kb at a given temperature
Therefore, if Ka of acid increases, then Kb of the conjugate base decreases. In other words, the conjugate base of strong acid is a weak base and vice-versa.
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