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7 Questions around this concept.
Does the variation in "g" due to the Earth's rotation affect the weight of objects?
Mass of earth-
Using Newton’s law of gravitation we can estimate the mass of the earth
$$
\begin{aligned}
& M=\frac{g R^2}{G} \simeq 10^{25} k g \\
& M \rightarrow \text { mass of earth }
\end{aligned}
$$
$G \rightarrow$ Gravitational constant
Density of Earth
$$
g=\frac{4}{3} \pi \rho G R
$$
Where,
$\rho \rightarrow$ density of earth
$\mathrm{So}_0 \rho=\frac{3 g}{4 \pi G R}$
$\rho=5478.4 \mathrm{~kg} / \mathrm{m}^3$
Inertial mass
Also known as the mass of material of the body which measures its inertia.
From Newton’s second law of motion
$$
\begin{aligned}
& F=m_i a \\
& m_i=\frac{F}{a}
\end{aligned}
$$
Where
$m_i \rightarrow$ inertial mass
$F \rightarrow$ external force
$$
a \rightarrow a c c^n
$$
Gravity has no effect on inertial mass.
Inertial mass is independent of the size, shape, and state of the body.
Gravitational Mass-
It is mass that determines the gravitational pull acting upon it.
Let F= gravitational pull on a body of mass
applying Newton’s law of gravitation
We have
$$
F=\frac{G M m_g}{R^2}
$$
So we get
$$
m_g=\frac{F}{G M / R^2}=\frac{F}{I}
$$
Where $m_g=$ Gravitational mass
$I \rightarrow$ Gravitational field intensity
Tip-Spring balance measures gravitational mass.
Mass (m)
It is the quantity of matter contained in the body.
Its SI unit- Kg
Its dimension is $[M]$
It is a scalar quantity.
It Can never be zero
Its value does not change with g.
Weight (W)
It is an Attractive force exerted by the earth on anybody.
S.I. Unit: Newton or Kg - wt
Dimension-$\left[M L T^{-2}\right]$
It is a vector quantity
It changes its value according to the value of g
At $\infty$ and at the center of the earth g = 0, So W is equal to zero there.
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