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    NEET 2026 Preparation Tips for Chemistry, Biology and Physics

    Second Order Reaction MCQ - Practice Questions with Answers

    Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

    Quick Facts

    • 11 Questions around this concept.

    Solve by difficulty

    The half-life of a second-order reaction is dependent on concentration of Reactant:-
     

    For a second-order reaction, if the concentration of the reactant is tripled, the rate of the reaction becomes:.
     

     A reaction follows second-order kinetics with the rate concentration of the reactant is 0.1 mott', what will be its concentration of ter 100 seconds?
     

    Concepts Covered - 1

    Second Order Kinetics

    Consider the reaction

    \mathrm{A\: \rightarrow \: P}

    For ssecond order reaction, the rate law is given as follows:

    \mathrm{Rate\: =\: k[A]^{2}\: =\: -\frac{dA}{dt}}

     

    • Integrated Rate Law: Since it is a second order reaction, thus:
      \mathrm{\frac{-dA}{dt}\: =\: k[A]^{2}}
      Integrating both sides, we get:
      \mathrm{\int_{A_{o}}^{A}\frac{dA}{A^{2}}\: =\: -\int_{0}^{t}kdt}

      where, Ao is the initial concentration of A at time t = 0
      A is the remaining concentration of A after time 't'

      \mathrm{\Rightarrow\left [ \frac{-1}{A} \right ]^{A}_{A_{o}}\: =\: -k(t)^{t}_{0}}

      \mathrm{\Rightarrow\left [ \frac{1}{A} \right ]^{A}_{A_{o}}\: =\: kt}

      \mathrm{\Rightarrow\: \frac{1}{A}\: -\: \frac{1}{A_{o}}\: =\: kt\quad\quad\quad\quad\quad\quad...............(i)}

      \mathrm{Thus, \mathbf{\frac{1}{[A]}\: =\: kt\: +\: \frac{1}{[A_{o}]}}}
       
    • Half-life(t1/2): We know that the half-life for a reaction is the time when the concentration of the reactant(A) is half of tis initial value.
      Thus, at time t = t1/2, A = Ao/2
      From equation (i) we have:

      \mathrm{t\: =\: \frac{1}{k}\left [ \frac{1}{A}\: -\: \frac{1}{A_{o}} \right ]}

      \mathrm{\Rightarrow t_{1/2}\: =\: \frac{1}{k}\left [ \frac{1}{A_{o}/2}\: -\: \frac{1}{A_{o}} \right ]}

      \mathrm{Thus,\: \mathbf{t_{1/2}\: =\: \frac{1}{kA_{o}}}}
      This is the half-life for the second-order reaction.

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    Second Order Kinetics

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