AC voltage applied to a resistor is considered one of the most asked concept.
7 Questions around this concept.
Given fig satisfies which of the following electrical circuit?

A $50 \Omega$ electric heater is connected to $100 \mathrm{~V}, 60 \mathrm{~Hz}$ are supply.
If the phase difference between voltage and current is $\frac{\pi}{6}$ and the resistance in the circuit is $\sqrt{300} \Omega$, then the impedance of the circuit will be
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If $\mathrm{V}=100 \sin (100 \mathrm{t}) \mathrm{V}$ and $\mathrm{I}=100 \sin \left(100 \mathrm{t}+\frac{\pi}{3}\right) \mathrm{mA}$ are the instantaneous values of voltage and current, then the RMS values of voltage and current are respectively:
AC voltage applied to a resistor:
When a constant voltage source or battery is applied across a resistor current is developed in resister. This current has a unique direction and flows from the negative terminal of a battery to positive terminal. The magnitude of the current remains constant as well. If the Direction of current through resistor changes periodically then the current is called alternating current.

Voltage V(t) is applied across resistance R. V(t) is sinusoidal voltage with peak Vm and time period T.
$$
T=\frac{1}{f}=\frac{2 \pi}{\omega}
$$
Where $f$ is frequency and $\omega$ is angular frequency. This kind of circuit is a purely resistive circuit. According to Kirchhoff's law -
$$
\begin{aligned}
v(t) & =R i(t) \\
i(t) & =\frac{v(t)}{R} \\
i(t) & =\frac{V_m \sin (\omega t)}{R} \\
i_m & =\frac{V_m}{R} \\
i(t) & =i_m \sin (\omega t)
\end{aligned}
$$
Here voltage and current has same frequency and both are in same phase. Therefore phase difference between current and voltage is 0 .
The maximum value of voltage is achieved at $\mathrm{t}=\mathrm{T} / 4$.
Peak current,
$$
i_0=\frac{V_0}{R}
$$
Power factor:
Ratio of resistance and impedance. The power factor also denoted by $\cos \phi$.
power factor $=\cos (\phi)=1$
Power:
$$
P=V_{r m s} i_{r m s}=\frac{V_0 i_0}{2}
$$
Time difference
$$
T . D .=0
$$
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