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Energy stored in an inductor is considered one the most difficult concept.
15 Questions around this concept.
Rate of increment of energy in an inductor with time in series LR circuit getting charged with a battery of e.m.f. E is best represented by: [ inductor has initially zero current ]
What is the time at which the rate of dissipation of energy (Joule's heat) across the resistance is equal to the rate at which magnetic energy is stored in the inductor?
An inductor coil of inductance L is divided into two equal parts and both parts are connected in parallel. The net inductance is :
The equivalent inductance between points P and Q in the figure is:
The dimension of $\sqrt{\frac{L}{\mathrm{C}}}$ is same as that of:
Shown in the figure is an R-L-C circuit. In a steady state, the ratio of energy stored in the inductor & capacitor is equal to
An inductor coil stores 32 J of magnetic energy and dissipates energy as heat at the rate of 320 W when a current of 4A is passed through it. What is the time constant of the circuit when this coil is joined across an ideal battery?
NAAC A+ Accredited| Ranked #24 in University Category by NIRF | Applications open for multiple UG & PG Programs
A solenoid of inductance 100 mH and resistance 20 is connected to a cell of emf 10 V. What is the energy stored in the inductor when the time t = 5 ln 2 milli sec?
A constant current flows in an R-L circuit. Then
A source emitting sound at a frequency of $f_0$ moves toward a stationary observer with a speed of $v_s=50 \mathrm{~m} / \mathrm{s}$. The speed of sound in air is $v=350 \mathrm{~m} / \mathrm{s}$. What is the apparent frequency heard by the observer if the actual frequency of the source is $f_0=500 \mathrm{~Hz}$?
Energy stored in an inductor (U)-
In building a steady current in the circuit, the source emf has to do work against the self-inductance of the coil and whatever energy
consumed for this work stored in the magnetic field of coil this energy called as magnetic potential energy (U) of the coil.
When an electric current i is flowing in an inductor, there is energy stored in the magnetic field. Considering a pure inductor L, the instantaneous power which must be supplied to initiate the current in the inductor is
$$
P=i v=L i \frac{d i}{d t}
$$
The work done by the voltage source during a time interval $d t$ is
$$
d W=P d t=i L \frac{d i}{d t} d t=L i d i
$$
total work $W$ done in establishing the final current $I$ in the inductor
$$
\mathrm{W}=\int_0^t P d t=\int_0^I L i d i=\frac{1}{2} L I^2
$$
So Energy stored in the magnetic field of the inductor is given as
$$
U=\frac{1}{2} L I^2
$$
The energy density (u)/Energy per unit volume-
$$
\text { using } U=\frac{1}{2} L I^2
$$
for the solenoid field. we can write
$\begin{aligned} & U=\frac{1}{2}(L i) i=\frac{N \phi i}{2} \\ & u=\frac{U}{V}=\frac{B^2}{2 \mu_0}\end{aligned}$
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