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Energy Stored In An Inductor - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Energy stored in an inductor is considered one the most difficult concept.

  • 9 Questions around this concept.

Solve by difficulty

The equivalent inductance between points P and Q in figure is :

Shown in the figure is a R-L-C circuit. In steady state the ratio of energy stored in the inductor & capacitor is equal to

A network of inductances, each of value 1H, is shown in figure. The equivalent inductance of the circuit between points A and B is

The magnetic potential energy stored in a certain inductor is 25mJ. When the current in the inductor is 60mA. This inductor is of inductance 

Concepts Covered - 1

Energy stored in an inductor

Energy stored in an inductor (U)-

In building a steady current in the circuit, the source emf has to do work against of self-inductance of the coil and whatever energy
consumed for this work stored in the magnetic field of coil this energy called as magnetic potential energy (U) of the coil.

When an electric current i is flowing in an inductor, there is energy stored in the magnetic field. Considering a pure inductor L, the instantaneous power which must be supplied to initiate the current in the inductor is

P=i v=L i \frac{d i}{d t}

The work done by the voltage source during a time interval $dt$ is

d W=P d t= i L \frac{d i}{d t} d t=L i d i

total work $W$ done in establishing the final current $I$ in the inductor

\text { W }=\int_{0}^{t} P d t=\int_{0}^{I} L i d i =\frac{1}{2} L I^{2}

So Energy stored in the magnetic field of the inductor is given as

U= \frac{1}{2}LI^{2}

 

The energy density (u)/Energy per unit volume-

using U= \frac{1}{2}LI^{2}

for the solenoid field, we can write 

  U=\frac{1}{2}(L i) i=\frac{N \phi i}{2} 

u=\frac{U}{V}= \frac{B^{2}}{2\mu _{0}}

 

 

 

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Energy stored in an inductor

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