Combination Of Capacitors - Parallel And Series MCQ - Practice Questions with Answers

Combination of capacitors:-

Capacitors can be combined in two ways.

1. Series

2. Parallel

Series combination:

If capacitors are connected in such a way that we can proceed from one point to another by only one path passing through all capacitors then all these capacitors are said to be in series.

  

Here three capacitors are connected in series and are connected across a battery of potential difference  ‘V’.

Charge:  'q' given by battery deposits at first plate of first capacitor. Due to induction it attract  '–q' on the opposite plate. The pairing +ve q charges are repelled to first plate of Second capacitor which in turn induce -q on the opposite plate. Same action is repeated to all the capacitors and in this way all capacitors get q charge. As a result ; the charge given by battery q, every capacitor gets charge q.

Potential difference:   V is the sum of potentials across all capacitors. Therefore

$\begin{array}{c}V=v_1+v_2+v_3\\ v_1=\frac{q_1}{c_1},v_2=\frac{q_2}{c_2},v_3=\frac{q_3}{c_3}\end{array}$

Equivalence equation: The equivalent capacitance for the combination of capacitance in series can be calculated as

$C_e=\frac{q}{V}$

Or,

$\begin{array}{rl}1/{\mathrm{C}}_{\mathrm{e}}& =\mathrm{V}/\mathrm{q}\\ & =({\mathrm{v}}_1+{\mathrm{v}}_2+{\mathrm{v}}_3)/\mathrm{q}\\ & ={\mathrm{v}}_1/\mathrm{q}+{\mathrm{v}}_2/\mathrm{q}+{\mathrm{v}}_3/\mathrm{q}\\ 1/{\mathrm{C}}_{\mathrm{e}}& =1/{\mathrm{C}}_1+1/{\mathrm{C}}_2+1/{\mathrm{C}}_3\end{array}$

For 2 capacitor system

$C=\frac{c_1{c}_2}{c_1+c_2},\text{ and }{v}_1=\frac{c_2}{c_1+c_2}\cdot V$

If n capacitor of capacitance 'c' are joint in series then equivalent capacitance

$C_e=\frac{c}{n}$
 

 

Parallel  combination: If capacitors are connected in such a way that there are many paths to go from one point to other. All these paths are parallel and capacitance of each path is said to be connected in parallel.

 

Here three capacitors are connected in parallel and are connected across a battery of potential difference  ‘V’.

The potential difference across each capacitor is equal and it is same as P.D. across Battery. The charge given by source is divided and each capacitor gets some charge. The total charge $q=q_1+q_2+q_3$.

Therefore, each capacitor has charge

${\mathrm{q}}_1={\mathrm{C}}_1{\mathrm{V}}_1,{\mathrm{q}}_2={\mathrm{C}}_2{\mathrm{V}}_2,{\mathrm{q}}_3={\mathrm{C}}_3{\mathrm{V}}_3$

Equivalent Capacitance : We know that, $q=q_1+q_2+q_3$ when divided by v both sides,

$\frac{q}{v}=\frac{{\mathrm{q}}_1}{v}+\frac{{\mathrm{q}}_2}{v}+\frac{{\mathrm{q}}_3}{v}$

Therefore the equivalence capacitance will be:

$\mathbf{C}=c_1+c_2+c_3$

The equivalent capacitance in parallel increases, and it is more than largest in parallel. In parallel combination V is same therefore

$v=\frac{q_1}{c_1}=\frac{q_2}{c_2}=\frac{q_3}{c_3}$

capacitance larger is charge.

Charge distribution : $q_1=c_{1}v,q_2=c_{2}v,q_3=c_{3}v$.

In 2 capacitor system charge on one capacitor

$q=\frac{c_1}{c_1+c_2+\dots }\cdot q$

Capacitors in parallel give $\mathrm{C}=\mathrm{nc}$.