End Correction - Practice Questions & MCQ

Quick Facts

End correction is considered one of the most asked concept.
3 Questions around this concept.

Solve by difficulty

If n₁, n₂ and n_{3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:}

A

$\frac{1}{n}=\frac{1}{n_{1}}+\frac{1}{n_{2}}+\frac{1}{n_{3}}$

B

$\frac{1}{\sqrt n}=\frac{1}{\sqrt n_{1}}+\frac{1}{\sqrt n_{2}}+\frac{1}{\sqrt n_{3}}$

C

$\sqrt n= \sqrt n_{1}+\sqrt n_{2}+\sqrt n_{3}$

D

$n =n_{1}+n_{2}+n_{3}$

Concepts Covered - 1

End correction

End correction -

In the organ pipe as we have studied in last concept, when the wave reaches the open end, due to collision particle sactters away from the pipe. Due to this the density reduces outside the pipe and form a rarer medium.

So, we can say that the wave is not exactly reflected back from the open end of the pipe. So, we can say that the antinodes will form always little away from the open ends. We can see this in the given figure. So the distance above the open end where an antinode is form is called end correction.

This end corrrection varies with radius of pipe and given as = $e = 0.6r$

Now taking the end correction into account, the frequency of a closed pipe of length $l$ can be given as -

$n_o = \frac{\nu}{4(l+e)}$ (One end open)

For open pipe -

$n_o = \frac{\nu}{2(l+2e)}$ (Both ends open)

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End correction

Concepts of Physics Part-1

Page No. : 339

Line : 51

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