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Moment Of Inertia Of A Disc MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Moment of inertia of a DISC is considered one of the most asked concept.

  • 17 Questions around this concept.

Solve by difficulty

The moment of inertia of a uniform semicircular disc of mass M and radius  r about a line  perpendicular to the plane of the disc through the center is :d

A circular disc X of radius R is made from an iron plate of thickness t  and another disc Y of radius 4R  is made from an iron plate of thickness t/4. Then the relation between the moment of inertia. I_{X} and I_{Y} is :

What is the moment of inertia of a disc having inner radius R1 and outer radius R2 about the axis passing through the center and perpendicular to the plane as shown in diagram? 

The moment of inertia of a uniform circular disc is maximum about an axis perpendicular to the disc and passing through:

 

A thin circular disk is in the xy plane as shown in the figure. The ratio of its
moment of inertia about z and z' axes will be :

Concepts Covered - 1

Moment of inertia of a DISC

Let I=Moment of inertia of a DISC about an axis through its center and perpendicular to its plane 

To calculate I 

Consider a circular disc of mass M, radius R, and center O.

And mass per unit area  = σ=MπR2

Take an elementary ring of mass dm of radius x as shown in figure

  So, dm=σ(2πxdx)=MπR2(2πxdx)dI=x2dmI=dI=0Rx2(MπR2(2πxdx))=2MR20Rx3dx=MR22

 

 

 

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Moment of inertia of a DISC

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