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Moment of inertia of a Rod is considered one of the most asked concept.
12 Questions around this concept.
The moment of inertia of a uniform cylinder of length and radius about its perpendicular bisector is . What is the ratio such that the moment of inertia is minimum?
Four identical thin rods each of mass M and length l, form a square frame. Moment of inetia of this frame aboit an axis through the centre of the square and perpendicular to its plane is
There is a rod of length L and mass M; one line is passing through the center of the rod and another line is passing through the end of the rod; The radius of gyrations ratio of this rod for the given cases (concerning the line positions) center/end is
A thin rod of length is suspended from a point from on its length which is at a distance from its centre, for what value of time period of oscillation will be minimum -
A thin rod of length is suspended from a point from on its length which is at a distance from its centre, for what value of time period of oscillation will be minimum-
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A thin rod (of mass and length ) is sliding keeping in contact with a vertical wall and a smooth surface as shown. of the rod about instantaneous axis of rotation at the instant shown is: -
A tube of length 1m is filled completely with an incompressible liquid with of mass 1kg and closed at both ends. The tube is rotated in a horizontal plane about one of its ends with a uniform angular velocity of 2rad/s. The force exerted by the liquid ath the other end is
Let I=Moment of inertia of a ROD about an axis through its centre and perpendicular to it
To calculate I (Moment of inertia of rod)
Consider a uniform straight rod of length L, mass M and having centre C
mass per unit length of the rod =
Take a small element of mass dm with length dx at a distance x from the point C.
Now integrate this dI between the limits
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