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Rate of Reaction - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Instantaneous Rate of Reaction is considered one the most difficult concept.

  • Factors Affecting Rate of Reaction, Factors Affecting Rate of Reaction(2) is considered one of the most asked concept.

  • 49 Questions around this concept.

Solve by difficulty

Consider the reaction 

\mathrm{B_2+2 A \stackrel{K_3}{\longrightarrow} 2 A B}            (slow)

If we increase the concentration of \mathrm{A_2} two times, then the rate of formation of AB will:-
 

Consider the reaction \mathrm{A+B \longrightarrow C}
the energy profile diagram for the reaction is given below:-

Question : what is the enthalpy of reaction \mathrm{\left(\Delta _{r} H\right)}.

Consider the reaction \mathrm{A+B \longrightarrow C}
the energy profile diagram for the reaction is given below:-

Question: Threshold energy of the reactant is

For the reaction, 2N_{2}O_{5}\rightarrow 4NO_{2}+O_{2},, the rate equation can be expressed in two ways -\frac{d\left [ N_{2}O_{5} \right ]}{dt}=k\left [ N_{2}O_{5} \right ]  and +\frac{d\left [ NO_{2} \right ]}{dt}=k'\left [ N_{2}O_{5} \right ]  

k\, and \, k'  are related as :

For the chemical reaction,

N_2(g) + 3H_2(g)\leftrightharpoons 2NH_3(g)

the correct option is:

 

In the reaction BrO_3^-(aq.)+5Br^-(aq.)+6H^+(aq.)\rightarrow 3Br_2+3H_2O

The rate of appearance of bromine (Br2) is related to rate of disappearance of bromide ions as following:

 

For the reaction, N_2O_{5(g)}\rightarrow 2NO_{2(g)}+\frac{1}{2}O_{2(g)} the value of the rate of disappearance of N2O5 is given as 6.25 \times 10^{-3}mol L^{-1} s^{-1} . The rate of formation of NO_2 and O_2 is given respectively as:

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Consider the reaction, 2A+B\rightarrow products. When concentration of B alone was doubled, the half­-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

The rate law for a reaction between the substances A and B  is given by rate =  k\left [ A \right ]^{n}\left [ B \right ]^{m}.

On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

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Concepts Covered - 5

Rate of Reaction

It is defined as "The rate of change of concentration of a reactant or a product per unit time" that is it is nothing but it is the per unit mole of rate of decomposition of any reactant or formation of product.

\text { Rate of reaction }(\mathrm{r})=\frac{\mathrm{C}_{1}-\mathrm{C}_{2}}{\mathrm{t}_{2}-\mathrm{t}_{1}}

As rate of reaction varies greatly with time, so generally, average reaction rate and instantaneous reaction rates are used. Average rate ways to is the rate at some particular instant of time and is equal to the time rate of change of the active mass of any of the reactants or any of the products.

\begin{array}{l}{\text { For a reaction A} \rightarrow \mathrm{P}} \\\\ {\text { Rate of disappearance of A}=\mathrm{-\frac{\Delta[A]}{\Delta T}}} \\\\ {\text { Rate of appearance of P} =\mathrm{-\frac{\Delta[P]}{\Delta T}}}\end{array}

            

Average Rate of Reaction

Change in the concentration of reactants or products per unit time is called average reaction velocity. If Δc is the change in the concentration of reactants and product in Δt time, then:

\text { Average velocity }=\mathrm{\pm \frac{\Delta c}{\Delta t}}

\mathrm{Unit \: of\: average \: velocity=\frac{Unit \: of \: concentration}{Unit\: of\:time}=\frac{gram\: mole}{litre\: second}={gram\: mole\: litre}^{-1}\: second^{-1}}

Instantaneous Rate of Reaction

As average reaction rate fails to predict rate at a particular moment of time so we use instantaneous rate which is equal to small change in concentration (dx) during a small interval of time (dt). It is given as dx/dt.

\mathrm{\lim _{\Delta t \rightarrow 0} \frac{\Delta c}{\Delta t}=\frac{d c}{d t}}

  • dx/dt = tanӨ = slope of curve
  • It can be written for any of the reactant or the product in terms of stoichiometric coefficients Vj which is negative for reactants and positive for products as follows:
    \frac{\mathrm{dx}}{\mathrm{dt}}=\frac{1}{\mathrm{V}_{\mathrm{j}}} \frac{\mathrm{d}(\mathrm{J})}{\mathrm{dt}}

    \mathrm{a A+b B \rightarrow c C+d D}

    \text { Rate w.r.t. }[\mathrm{A}]=-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}} \times \frac{1}{\mathrm{a}}

    \text { Rate w.r.t. }[\mathrm{B}]=-\frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}} \times \frac{1}{\mathrm{b}}

    \text { Rate w.r.t. }[\mathrm{C}]=-\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}} \times \frac{1}{\mathrm{c}}

    \text { Rate w.r.t. }[\mathrm{D}]=-\frac{\mathrm{d}[\mathrm{D}]}{\mathrm{dt}} \times \frac{1}{\mathrm{d}}
  • For the reactants, negative sign indicates decrease of concentration and for products positive sign indicates increase in concentration.
  • For a reversible reaction at dynamic equilibrium, net reaction rate is always zero as:
    (\mathrm{d} \mathrm{x} / \mathrm{dt})_{\mathrm{f}}=(\mathrm{d} \mathrm{x} / \mathrm{dt})_{\mathrm{B}}
Factors Affecting Rate of Reaction

There are various factors on which the rate of reaction depends:

  • Nature of reactant and product: 
    • For ionic reactants reaction rate is fast as activation energy is zero for them. For example:
      \mathrm{BaCl}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+2 \mathrm{HCl}
    • Molecules have slow reaction rate due to need of more activation energy. For example:
      2 \mathrm{CO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{CO}_{2}
  • Physical state of reactants: Rate also changes with physical state.
    Gaseous states > Liquid states > Solid states
  • Pressure: For gaseous reactants rate varies with pressure just like concentration.
    \frac{\mathrm{d} \mathrm{x}}{\mathrm{dt}} \propto \text {Pressure }(\text {as } \mathrm{P} \propto \mathrm{C})
  • Surface Area: Greater the surface area, faster is the rate of reaction due to more number of active sites.
    \text { Rate }(\mathrm{dx} / \mathrm{dt}) \propto \text {Surface area }
Factors Affecting Rate of Reaction(2)
  • Temperature: Rate of reaction increases with the increase of temperature as it increases the number of effective collisions. It is observed that for every 10oC rise in temperature -dx/dt or rates become double to triple as the number of molecules with every greater than activation energy becomes two-three times.
    \mathrm{\text { Temp. Coefficient }(\mu)=\frac{K \text { at } t^{\circ} C+10^{\circ} \mathrm{C}}{K \text { at } t^{\circ} \mathrm{C}}}
    The value of temperature coefficient lies in between 2-3. In case we increase the temperature by more than 10oC the above relation can be given as:
    \frac{\mathrm{K}_{\mathrm{T}_{2}}}{\mathrm{K}_{\mathrm{T}_{1}}}=\mathrm{(\mu)^{\Delta T/10}}
    \text {[Here}\left.\Delta \mathrm{T}=\mathrm{T}_{2}-\mathrm{T}_{1}\right]

    \log _{10} \frac{\mathrm{K}_{\mathrm{T}_{2}}}{\mathrm{K}_{\mathrm{T}_{1}}}=\frac{\Delta \mathrm{T}}{10} \log _{10} \mu

    \frac{\mathrm{K}_{\mathrm{T}_{2}}}{\mathrm{K}_{\mathrm{T}_{1}}}=\text {Antilog}\left[\frac{\Delta \mathrm{T}}{10} \log _{10} \mu\right]
     
  • Catalyst: It increases the rate of a reaction by decreasing the activation energy by accepting a new alternative smaller path for the reaction. It is reverse in case of negative catalyst to that of positive catalyst. Catalysts are more effective in 'Solid powdered form' due to larger surface area, that is, more active sites.
  • Intensity of light: Rate of photochemical reactions depends upon intensity of light radiations.
    \frac{\mathrm{dx}}{\mathrm{dt}} \propto \text {Intensity of radiation }
  • Concentration of reactants: Rate increases with the increase of concentration as due to more number of reactants there are more collisions.
    \text { Rate of reaction }(\mathrm{dx} / \mathrm{dt}) \propto \text {Concentration}

Study it with Videos

Rate of Reaction
Average Rate of Reaction
Instantaneous Rate of Reaction

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