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Relation between electric field and potential is considered one of the most asked concept.
32 Questions around this concept.
Assume that an electric field exists in space. Then the potential difference VA - VO, where VO is the potential at the origin and VA the potential at x=2 m is :
An electric field is given by kN/C. The potential of the point (1, –2), if potential of the point (2, 4) is taken as zero, is
The electric potential V at any point (x, y, z), all in meters in space is given by V = 4x2 volt. The electric field at the point (1, 0, 2) in volt/meter is
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Electric field and potential are related as
Where E is Electric field
And V is Electric potential
And r is the position vector
And Negative sign indicates that in the direction of intensity the potential decreases.
Then
where
(partial derivative of V w.r.t. x)
(partial derivative of V w.r.t. y)
(partial derivative of V w.r.t. z)
Proof-
Let the Electric field at a point r due to a given mass distribution is E.
If a test charge q is placed inside a uniform Electric field E.
Then force on a charged particle q when it is at r is as shown in figure
As the particle is displaced from r to r + dr the
work done by the Electric force on it is
Electric potential V is defined as negative of work done per unit charge
So Integrating between r1, and r2
We get
If r1=r0, is taken at the reference point, V(r0) = 0.
Then the potential V(r2=r) at any point r is
in Cartesian coordinates, we can write
Then
So
If y and z remain constant, dy = dz = 0
Thus
Similarly
As Electric field and potential are related as
and E=constant then
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