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Stefan Boltzmann Law MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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  • Stefan Boltzmann law is considered one of the most asked concept.

  • 2 Questions around this concept.

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Stefan Boltzmann law

 

  • According to Stefan Boltzmann law, the radiant energy emitted by a perfectly black body per unit area per sec is directly proportional to the fourth power of its absolute temperature,

       or emissive power of the black body is directly proportional to the fourth power of its absolute temperature (\theta).

     i.e  E\;\alpha\; \theta^{4}

          \Rightarrow\ E=\sigma\theta^{4}

where 

\sigma=Stefan's constant

and its value is

\sigma=5.67\times 10^{-8}W/m^{2}K^{4}

  • For ordinary body

            1.  Emissive power is  given by  e=\epsilon E

           So according to Stefan Boltzmann law

   e=\epsilon E=\epsilon \sigma \theta^{4}

where  \epsilon = represent emissivity of the material

2. Radiant energy-

If Q is the total energy radiated by the ordinary body then

e= \frac{Q}{A\times t}=\epsilon \sigma \theta^{4}\Rightarrow Q=A\epsilon \sigma \theta^{4}t

3. Radiant power (P): It is defined as the energy radiated per unit area.

i.e   P=\frac{Q}{t}=A\epsilon \sigma \theta^{4}

4.  If an ordinary body at temperature \theta is surrounded by a body at a temperature  \theta _0

                    Then according to Stefan Boltzmann law

                                e =\epsilon \sigma (\theta^{4}-\theta_0^{4})

 

 

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