Careers360 Logo
NEET Marks vs Rank 2023 - NEET Marks vs Percentile

Stokes' Law And Terminal Velocity MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Stokes' law & Terminal Velocity is considered one the most difficult concept.

  • 29 Questions around this concept.

Solve by difficulty

Spherical balls of radius R are falling in a viscous fluid of viscosity \eta with a velocity\nu. The retarding viscous force acting on the spherical ball is:

A spherical solid ball of volume V is made of a material of density \rho1. It is falling through a liquid of density \rho2 (\rho2  < \rho1). Assume that the liquid applies a viscous force on the ball that is proportional to the square of its speed \nu ,i.e.,F_{viscous}= -kv^{2}\left ( k> 0 \right ). The terminal speed of the ball is

Which of the following options correctly describes the variation of the speed v and acceleration ‘a’ of a point mass falling vertically in a viscous medium that applies a force F =−kv, where ‘k’ is a constant, on the body? (Graphs are schematic and not drawn to scale)

From amongst following curves, which one show the variation of the velocity v with time t for a small-sized spherical body (release from rest) falling vertically downwards in a long column of a viscous liquid is best represented by

 

If the terminal speed of a sphere of gold \left ( density = 19.5 kg/m^{3} \right ) is 0.2 m/s in a viscous liquid \left ( density = 1.5 kg/m^{3} \right ), find the terminal speed (in m/sec) of a sphere of silver \left ( density = 10.5 kg/m^{3} \right ) of the same size in the same liquid.

Concepts Covered - 1

Stokes' law & Terminal Velocity
  • Stokes' law-

When a body moves through a fluid then The fluid exerts a viscous force on the body to oppose its motion.

And according to Stokes' law, the magnitude of the viscous force depends on the shape and size of the body, its speed and the viscosity of the fluid.

So for the below figure

If a sphere of radius r moves with velocity through a fluid of viscosity η.
Then using Stokes' law the viscous force ( F ) opposing the motion of the sphere is given by

F=6πηrv


Where

η coefficient viscosity 

r radius
v - velocity

  • Terminal Velocity-

When the spherical body is dropped in a viscous fluid, it is first accelerated and then its acceleration becomes zero and it attains a constant velocity and this constant velocity is known as terminal velocity.

For a spherical body of radius r is dropped in a viscous fluid, The forces acting on it are shown in the below figure.

 

So Forces acting on the body are

1. Weight of Body (W)

W=mg=43πr3ρg


Where ρ density of body
2. Buoyant/ Thrust Force (T of FB)

T=FB=43πr3σg

where σ density of fluid
3. Viscous force ( F )

F=6πηrv


So when the body attains terminal velocity the net force acting on the body is zero.
Apply force balance

FB+F=W6πηrv+43πr3σg=43πr3ρg6πηrv=43πr3g(ρσ)vt=29r2(ρσ)ηg


Where vT= terminal velocity

                From this formula, we can say that

  • Terminal velocity depends on the radius of the sphere/body.
  • Greater the density of solid greater the terminal velocity     
  • Greater the density and viscosity of the fluid lesser the terminal velocity.      
  • If ρ > σ then Terminal velocity will be positive.

            i.e., the Spherical body attains constant velocity in a downward direction.     

  •  If ρ < σ then Terminal velocity will be negative.

         i.e., the Spherical body attains constant velocity in an upward direction.

  •  Terminal velocity graph

                  

 

 

Study it with Videos

Stokes' law & Terminal Velocity

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Books

Reference Books

Stokes' law & Terminal Velocity

Physics Part II Textbook for Class XI

Page No. : 264

Line : 5

E-books & Sample Papers

Get Answer to all your questions

Back to top