Stokes' Law And Terminal Velocity MCQ - Practice Questions with Answers

• Stokes' law-

When a body moves through a fluid then The fluid exerts a viscous force on the body to oppose its motion.

And according to Stokes' law, the magnitude of the viscous force depends on the shape and size of the body, its speed and the viscosity of the fluid.

So for the below figure

If a sphere of radius $r$ moves with velocity $\vee$ through a fluid of viscosity $\eta$.
Then using Stokes' law the viscous force ( F ) opposing the motion of the sphere is given by

$$
F=6 \pi \eta r v
$$

Where

$$
\eta-\text { coefficient viscosity }
$$

$r-$ radius
$v$ - velocity

• Terminal Velocity-

When the spherical body is dropped in a viscous fluid, it is first accelerated and then its acceleration becomes zero and it attains a constant velocity and this constant velocity is known as terminal velocity.

For a spherical body of radius r is dropped in a viscous fluid, The forces acting on it are shown in the below figure.

So Forces acting on the body are

1. Weight of Body (W)

$$
W=m g=\frac{4}{3} \pi r^3 \rho g
$$

Where $\rho \rightarrow$ density of body
2. Buoyant/ Thrust Force (T of $F_{B)}$

$$
T=F_B=\frac{4}{3} \pi r^3 \sigma g
$$

where $\sigma \rightarrow$ density of fluid
3. Viscous force ( $F$ )

$$
F=6 \pi \eta r v
$$

So when the body attains terminal velocity the net force acting on the body is zero.
Apply force balance

$$
\begin{aligned}
& F_B+F=W \\
& \rightarrow 6 \pi \eta r v+\frac{4}{3} \pi r^3 \sigma g=\frac{4}{3} \pi r^3 \rho g \\
& \rightarrow 6 \pi \eta r v=\frac{4}{3} \pi r^3 g(\rho-\sigma) \\
& \rightarrow v_t=\frac{2}{9} \frac{r^2(\rho-\sigma)}{\eta} g
\end{aligned}
$$

Where $v_T=$ terminal velocity

                From this formula, we can say that

• Terminal velocity depends on the radius of the sphere/body.
• Greater the density of solid greater the terminal velocity     
• Greater the density and viscosity of the fluid lesser the terminal velocity.      
• If ρ > σ then Terminal velocity will be positive.

            i.e., the Spherical body attains constant velocity in a downward direction.     

•  If ρ < σ then Terminal velocity will be negative.

         i.e., the Spherical body attains constant velocity in an upward direction.

•  Terminal velocity graph