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Thermal Expansion In Liquids And Gases MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Thermal Expansion in liquids and gases is considered one the most difficult concept.

  • 22 Questions around this concept.

Solve by difficulty

A metal bar of length L and area of cross-section A is rigidly clamped between two walls. The Young's modulus of its material is Y and the coefficient of linear expansion is \mathrm{\alpha.} The bar is heated so that its temperature increases by \mathrm{\theta^{\circ} \mathrm{C}}. Then the force exerted at the ends of the bar is given by

In a vertical U-tube containing a liquid, the two arms are maintained at different temperatures t1 and t2. The liquid columns in the two arms have heights of l1 and l2 respectively. The coefficient of volume expansion of the liquid is equal to : 

The reading of the air thermometer at 0°C and 100°C are 50 cm and 75 cm of mercury respectively. The temperature at which its reading is 80 cm of the mercury column is - 

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A mercury thermometer read 80^{\circ} \mathrm{C} when the mercury is at 5.2 \mathrm{~cm} mark and 60^{\circ} \mathrm{C}  when the mercury is at 3.9 \mathrm{~cm} mark. Find the temperature when the mercury level is at the mark is  4×10x. Find the value of x.

Concepts Covered - 1

Thermal Expansion in liquids and gases

Thermal Expansion in Liquids

  • Like solids, liquids do not have linear and superficial expansion but liquid only undergoes volume expansion.

 

  • We always need some solid vessel to keep the liquid, so liquids are always to be heated along with a vessel which contains them so initially on heating the system (System is liquid + vessel here). Initially the level of liquid in vessel falls (vessel expands more since it absorbs heat and liquid expands less) as the volume expansion co-effecient of solid is more than that of liquid but later on, it starts rising due to faster expansion of the liquid (because now solid transfer all the heat to liquid and that is the condition of steady state)

                                        

So, from above we can conclude that the actual increase in the volume of the liquid = The apparent increase in the volume of liquid + the increase in the volume of the vessel.

Basically liquids have two coefficients of volume expansion - 

  1. Co-efficient of apparent expansion \gamma _a: It is due to apparent (Apparent means that appears but not real) increase in the volume of liquid. This happens when expansion of vessel containing the liquid is not taken into account.

                                      \gamma_{a}=\frac{\text { Apparent expansion in volume }}{\text { Initial vdume } \times \Delta \theta}=\frac{(\Delta V)_{o}}{V \times \Delta \theta}

        2. Co-efficient of real expansion \gamma _r : It is due to the actual increase in volume of liquid due to heating. In                                    this expansion of vessel containing the liquid is taken into account.

                                       \gamma_{r}=\frac{\text { Real increase in volume }}{\text { Initial vdume } \times \Delta \theta}=\frac{(\Delta V)}{V \times \Delta \theta}

 

Also coefficient of expansion of flask \gamma_{vessel} = \frac{\Delta V_{vessel}}{V \times \Delta \theta}

So, \gamma_{\text {Real }}=\gamma_{\text {Apporent }}+\gamma_{\text {Vessel }}

So the change (apparent change) in volume in liquid relative to vessel is -  

                      \Delta V_{a p p}=V \gamma_{a p p} \Delta \theta=V\left(\gamma_{\text {Real }}-\gamma_{\text {Vessel}}\right) \Delta \theta=V\left(\gamma_{r}-3 \alpha\right) \Delta \theta

Where, \alpha=\text { Coefficient of linear expansion of the vessel. }

Anomalous expansion of water : Generally any material expands on heating and contracts on cooling. But in case of water, it expands on heating if its temperature is greater than 4°C. In the range 0°C to 4°C, water contracts on heating and expands on cooling, i.e. \gamma is negative. So water have tgis special property, which is not found in any existing natural material. This behaviour of water in the range from 0°C to 4°C is called anomalous expansion. Yo can see it with the help of graph.


This is the anomalous behaviour of water which causes ice to form first at the surface of a lake in cold weather. So, as winter approaches, the water temperature increases initially at the surface. It results the water sinks because of its increased density. Consequently, the surface reaches 0°C first and because of that the lake becomes covered with ice. This property of water makes the aquatic life to survive the cold winter as the lake bottom remains unfrozen at a temperature of about 4°C.


At 4°C, density of water is maximum while its specific volume is minimum.

                                                       

 

Variation of Density with Temperature -

Most substances (solid and liquid) expand heat is supplied to them, i.e., volume of a given mass of a substance increases on heating, so the density should decrease \left(\text { as } \rho \propto \frac{1}{V}\right) . It means that the density is inversely proportional to the volume. From that we can deduce the expression of density after heating or cooling as follows - 

                                          So,         \\ {\frac{\rho^{\prime}}{\rho}=\frac{V}{V^{\prime \prime}}=\frac{V}{V+\Delta V}=\frac{V}{V+\gamma^{N \Delta \theta}}=\frac{1}{1+\gamma \Delta \theta}} \\ \\ \\ {\Rightarrow \rho^{\prime}=\frac{\rho}{1+\gamma \Delta \theta}=\rho(1+\gamma \Delta \theta)^{-1}=\rho(1-\gamma \Delta \theta)}

Here, \rho \ and \ \rho' \ is \ the \ density \ before \ and \ after \ heating \ the \ material

 

Expansion of Gases - 

As we know that the gases have no definite shape. It takes the shape of the vessel in which it is kept. Therefore gases have only volume expansion. Since the expansion of container (Because the container is solid) is negligible in comparison to the gases, therefore gases have only real expansion.

(1) Coefficient of volume expansion : At constant pressure, the unit volume of a given mass of a gas, increases with 1°C rise of temperature, is called coefficient of volume expansion.

                                     \alpha=\frac{\Delta V}{V_{0}} \times \frac{1}{\Delta \theta} \Rightarrow \text { Final volume } V^{\prime}=V(1+\alpha \Delta \theta)

(2) Coefficient of pressure expansion : 

                                     \beta=\frac{\Delta P}{P} \times \frac{1}{\Delta \theta}

                                     \therefore \text { Final pressure } P^{\prime}=P(1+\beta \Delta \theta)

 

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Thermal Expansion in liquids and gases

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