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Thermal Stress And Thermal Strain MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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  • Thermal stress and thermal strain is considered one of the most asked concept.

  • 11 Questions around this concept.

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A metal rod of young modulus $Y$ and coefficient of thermal expansion $\alpha$ is held at its two ends such that its length remains invariant. If its temperature is raised by $t^{\circ} \mathrm{C}$ the linear stress developed in it is

When a force is applied at one end of an elastic wire, it produces a strain $\varepsilon$ in the wire. If $Y$ is Young's modulus of the material of the wire, the amount of energy stored per unit volume of the wire is given by

A wire, suspended vertically from one end, is stretched by attaching a weight of 20 N to the lower end. The weight stretches the wire by 1 mm. How much energy is gained by the wire?

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A steel rod of diameter 1 cm is clamped firmly at each end when its temperature is $25^{\circ} \mathrm{C}$. So that it can't contract on cooling. The tension in the road $0^{\circ} \mathrm{C}$ is approximate. (Take, $\alpha=10^{-5} 1^{\circ} \mathrm{c}, y=2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$ )

The temperature of a body on kelvin scale is found to be x ~K. When it is measured by fahrenheit thermometer, it is found to be x ^{0}F, then the value of x is -

Concepts Covered - 1

Thermal stress and thermal strain

Thermal stress in a  rod which is rigidly fixed : When a rod which rigidly fixed at ends such as to prevent expansion or contraction, when its temperature is increased or decreased. Due to preventing its thermal expansion or contraction, a compressive or tensile stress is developed in it. As the rod try to expand or contracts, then it apply a reaction force on the rigid support. If the change in temperature of a rod of length L is \Delta \theta then - 

                                             \text { Thermal strain }=\frac{\Delta L}{L}=\alpha \Delta \theta \quad\left[\text { As } \alpha=\frac{\Delta L}{L} \times \frac{1}{\Delta \theta}\right]

                                     

As, If we know the strain then with the help of Hooke's law, we can find the stress also. If we know the stress , then we can find the force by multiplying cross-sectional area with stress. Both stress and force can be written as - 

\\ {\text { So, Thermal stress }=Y \alpha \Delta \theta} \\ {\text { or, Force on the supports } F=Y A \alpha \Delta \theta}

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Thermal stress and thermal strain

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Thermal stress and thermal strain

Physics Part II Textbook for Class XI

Page No. : 283

Line : 17

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