Pearson | PTE
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Thermal stress and thermal strain is considered one of the most asked concept.
14 Questions around this concept.
A metal rod of young modulus $Y$ and coefficient of thermal expansion $\alpha$ is held at its two ends such that its length remains invariant. If its temperature is raised by $t^{\circ} \mathrm{C}$ the linear stress developed in it is
A wooden wheel of radius R is made of two semicircular parts (see figure); The two parts are held together by a ring made of a metal strip of cross sectional area S and length L . L is slightly less than $2 \pi R$ To fit the ring on the wheel, it is heated so that its temperature rises by $\Delta T$ and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semicircular parts together. If the coefficient of linear expansion of the metal is $\alpha$ and its Youngs' modulus is Y , the force that one part of the wheel applies on the other part is :
When a force is applied at one end of an elastic wire, it produces a strain $\varepsilon$ in the wire. If $Y$ is Young's modulus of the material of the wire, the amount of energy stored per unit volume of the wire is given by
A wire, suspended vertically from one end, is stretched by attaching a weight of 20 N to the lower end. The weight stretches the wire by 1 mm. How much energy is gained by the wire?
A steel rod of diameter 1 cm is clamped firmly at each end when its temperature is $25^{\circ} \mathrm{C}$. So that it can't contract on cooling. The tension in the road $0^{\circ} \mathrm{C}$ is approximate. (Take, $\alpha=10^{-5} 1^{\circ} \mathrm{c}, y=2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$ )
The temperature of a body on kelvin scale is found to be $x~K$. When it is measured by Fahrenheit thermometer, it is found to be $x^\circ F$, then the value of $x$ is -
The hexose monophosphate shunt pathway takes place when there is
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A metallic bar of Young’s modulus,$0.5 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ and coefficient of linear thermal expansion $10^{-5}{ }^{\circ} \mathrm{C}^{-1}$, length 1 m and area of cross-section 10–3 m2 is heated from 0°C to 100°C without expansion or bending. The compressive force developed in it is :
Thermal stress in a rod that is rigidly fixed: When a rod which rigidly fixed at ends such as to prevent expansion or contraction, when its temperature is increased or decreased. Due to preventing its thermal expansion or contraction, compressive or tensile stress is developed in it. As the rod tries to expand or contract, then it applies a reaction force on the rigid support. If the change in temperature of a rod of length $L$ is $\Delta \theta$ then -
$$
\text { Thermal strain }=\frac{\Delta L}{L}=\alpha \Delta \theta \quad\left[\text { As } \alpha=\frac{\Delta L}{L} \times \frac{1}{\Delta \theta}\right]
$$
If we know the strain then with the help of Hooke's law, we can find the stress also. If we know the stress, then we can find the force by multiplying the cross-sectional area with stress. Both stress and force can be written as -
So, Thermal stress $=Y \alpha \Delta \theta$ or,
Force on the supports $F=Y A \alpha \Delta \theta$
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