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Work, Energy And Power For Rotating Body MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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  • Work, Energy and Power for Rotating Body is considered one of the most asked concept.

  • 9 Questions around this concept.

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Two rotating bodies A and B of masses m and 2m with moments of inertia IA and I_B \left( {I_B > I_A } \right) have equal kinetic energy of rotation. If LA and LB are their angular momenta respectively, then

when a sphere of moment of inertia.\mathrm{ 'I'} rolls down on an inclined plane then percentage of rotational kinetic energy will be -
 

An object of mass '2kg' is rotating with an angular velocity of '1rad/s' about an axis that is '1m' away from the centre of mass. If the radius of gyration of this object is '2m'. Then rotational kinetic energy of the body is given by:

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Concepts Covered - 1

Work, Energy and Power for Rotating Body
  1. Work-

For translation motion

$$
W=\int F d s
$$


So for rotational motion

$$
W=\int \tau d \theta
$$
 

  1. Rotational kinetic energy-

The energy a body has by virtue of its rotational motion is called its rotational kinetic energy.

 

   

 

Rotational kinetic energy

Translatory kinetic energy

1

$K_R=\frac{1}{2} I \omega^2$

  

$K_T=\frac{1}{2} m V^2$

 

2

$K_R=\frac{1}{2} I \omega$

  

$K_T=\frac{1}{2} P V$

 

3

$K_R=\frac{L^2}{2 I}$

 

$K_T=\frac{P^2}{2 m}$

 

 

  1. Power =Rate of change of kinetic energy  

For translation motion $P=\vec{F} \cdot \vec{V} P=\vec{F} \cdot \vec{V}$
So for rotational motion

$$
P=\frac{d\left(K_R\right)}{d t}=\frac{d\left(\frac{1}{2} I \omega^2\right)}{d t}=I \omega \frac{d \omega}{d t}=I \alpha \omega=\tau \cdot \omega
$$


Or $P=\vec{\tau} \cdot \vec{\omega}$

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Work, Energy and Power for Rotating Body

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