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Resonance In Series LCR Circuit - Practice Questions & MCQ

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Resonance in Series LCR circuit is considered one the most difficult concept.

  • 15 Questions around this concept.

Solve by difficulty

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In a  LCR circuit capacitance is changed from C to 2C . For the resonant frequency to remain unchanged, the inductance should be changed from L to

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In a series LCR circuit, the inductance L is 10 mH, capacitance C is 1µF and resistance R is 100 \ \Omega . The frequency at which resonance occurs is?

Concepts Covered - 1

Resonance in Series LCR circuit

Resonance in Series LCR circuit-

As we have discusssed that when- 

                                              \omega L = \frac{1}{\omega C} ,

then tanφ is zero i.e. phase angle (φ) is zero and voltage and current are in phase. We have called it electric resonance. So, if X_L = X_C, then the equation of impedence become - 

                                                                    Z=\sqrt{R^{2}+\left(\omega L-\frac{1}{\omega C}\right)^{2}}=R

So, we get minimum value of Z. 

In this case impedance is purely resistive and minimum and currents has its maximum value. Now as - 

 

                                                                                \omega L = \frac{1}{\omega C}

                                                                So,

                                                                                   \omega = \frac{1}{\sqrt{LC}}

As,  \omega = 2 \pi f_o.  Where f_o is the frequency of applied voltage.

                                   

                                                                So,

                                                                              f_o = \frac{1}{2 \pi \sqrt{LC}}

This frequency is called resonant frequency of the circuit. 

Peak current in this case is given by - 

                                                                            i_o = \frac{V_o}{R}

We will now discuss about the resonance curve and its nature. We will show the variation in circuit current (peak current i0) with change in frequency of the applied voltage - 

                                   

This figure/graph shows the variation of current with the frequency. 

Conclusions from the graph - 

1. If R has small value, the resonance is sharp which means that if applied frequency is lesser to resonant frequency f0,the current is high otherwise

2. If R is large, the curve is broad sided which means that those is limited change in current for resonance and non -resonance conditions

                  

Note -                                

The natural or resonant frequency is Independent from resistance of the circuit.

                                     X_{L}=X_{c}= \omega _{0}L= \frac{1}{\omega _{0}c}

                                                    \nu _{0}= \frac{1}{2\pi \sqrt{Lc}}\left ( Hz \right )

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Resonance in Series LCR circuit

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