NEET Biometric Attendance 2025 by NTA - Check Attendance Rules

Gibbs Energy Change And Criteria For Equilibrium MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Spontaneity Criteria With Gibbs Energy (G) is considered one the most difficult concept.

  • Gibbs Energy And Change In Gibbs Energy is considered one of the most asked concept.

  • 39 Questions around this concept.

Solve by difficulty

For a particular reversible reaction at temperature  T,\Delta H\: and \: \Delta S\: were found to be both +Ve.

If T_{e} is the temperature at equilibrium, the reaction would be spontaneous when

Standard entropy of \mathrm{ X_{2},Y_{2}\; and\; XY_{3}}  are 60, 40 and 50 J K-1 mol-1, respectively. For the reaction,

\mathrm{\frac{1}{2} X_{2}+\frac{3}{2} Y_{2}\rightarrow XY_{3},\; \Delta H=-30\, kJ} to be at equilibrium, the temperature will be

Match list - 1 (Equations) with list - 2  (Type of processes) and select the correct option

    List 1                                                                            List 2

  Equations                                                                    Type pf process

(1) K_{p}> Q                                                                 (i) Non spontaneous

(2) \Delta G^{o}< RT\ In\ Q                                               (ii) Equilibrium

(3) K_{p}=Q                                                                 (iii) spontaneous and                                                                                                                endothermic

(4) T> \frac{\Delta H}{\Delta S}                                                               (iv) spontaneous

NEET 2024: Cutoff (OBC, SC, ST & General Category)

NEET 2024 Admission Guidance: Personalised | Study Abroad

NEET 2025: SyllabusMost Scoring concepts NEET PYQ's (2015-24)

NEET PYQ's & Solutions: Physics | ChemistryBiology

In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is

CH_{3}OH_{\left ( l \right )}+\frac{3}{2}O_{2\left ( g \right )}\rightarrow CO_{2\left ( g \right )}+2H_{2}O_{\left ( l \right )}

At 298 K standard Gibb’s energies of formation for CH_{3}OH_{\left ( l \right )},H_{2}O_{\left ( l \right )}\: and\: CO_{2\left ( g \right )}

are –166.2, –237.2 and –394.4 kJ mol-1 respectively. If standard enthalpy of combustion of methanol is –726 kJ mol-1 , efficiency of the fuel cell will be

For the reactions,

$\begin{array}{ll}\mathrm{C}+\mathrm{O}_2 \rightarrow \mathrm{CO}_2 ; & \Delta \mathrm{H}=-393 \mathrm{~J} \\ 2 \mathrm{Zn}+\mathrm{O}_2 \rightarrow 2 \mathrm{ZnO} ; & \Delta H=-412 J\end{array}$

If an endothermic reaction is non­-spontaneous at the freezing point of water and becomes feasible at its boiling point, then

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is:

Pearson | PTE

Register now for PTE & Unlock 20% OFF : Use promo code: 'C360SPL20'. Valid till 31st DEC'24! Trusted by 3,500+ universities globally

For a given reaction, $\Delta H=35.5 \mathrm{kJmol}^{-1}$ and $\Delta S=83.6 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$. The reaction is spontaneous at :(Assume that $\Delta H$ and $\Delta S$ do not vary with tempearature)

Which of the following statements is correct for a reversible process in a state of equilibrium?

Most Scoring concepts for NEET
This ebook serves as a valuable study guide for NEET exams, specifically designed to assist students in light of recent changes and the removal of certain topics from the NEET exam.
Download EBook

For a rxn \mathrm{2 A B_2(g)\rightleftharpoons A_2 B_2(g)} when \mathrm{\Delta S=-163.0 \, \mathrm{JK}^{-1}} and  \mathrm{\Delta H=-69.48 \, \mathrm{kJ} \, \mathrm{mol}^{-1}} What will be the magnitude of \mathrm{\Delta G} at 298 \mathrm{~K}

Concepts Covered - 3

Gibbs Energy And Change In Gibbs Energy

It was introduced in order to relate H, S and to explain spontaneity. According to J. Willard Gibb's Free energy of a system is defined as the maximum amount of energy available to a system during a process that can be converted into useful work. 

or 

It is the thermodynamic quantity specially characterizing the system, the decrease in whose value during a process is equal to the useful work done by the system. 

 

It is denoted by G and it is given mathematically as follows: 

\mathrm{G = H-TS}

Here,

H = Enthalpy

T = Absolute Temperature

S = Entropy

Also, we learnt that 

\mathrm{H = E + PV}

\mathrm{G = E + PV - TS}

 

Therefore, Free energy change at constant temperature and pressure is given as:

\\ \mathrm{\Delta G = \Delta E + P\Delta V - T\Delta S} \\\\ \mathrm{As\ \Delta H = \Delta E + P\Delta V} \\\\ \mathrm{So,\ \Delta G = \Delta H - T\Delta S}

At standard condition that is, 298 K and 1 atm pressure

\\ \mathrm{\ \Delta G^o = \Delta H^o - T\Delta S^o }

It is called Gibbs equation and it is used to explain criterion of spontaneity, driving force etc.

It is a state function and an extensive property. 

 

Gibb's Free Energy change for a Reaction

For a general reaction, it can be given as follows: 

\\ \mathrm{pA + qB \rightarrow rC+sD}\\ \\ \begin{array}{l}{\Delta \mathrm{G}^{\circ}=\sum \Delta \mathrm{G}_{\mathrm{P}}^{\circ}-\sum \Delta \mathrm{G}_{\mathrm{R}}^{\circ}}\\ \\ {=\left[\left(\mathrm{r} \sum \mathrm{G}_{\mathrm{C}}^{\circ}+\mathrm{s} \sum \Delta \mathrm{G}_{\mathrm{D}}^{\circ}\right)-\left(\mathrm{p} . \sum \Delta \mathrm{G}_{\mathrm{A}}^{\circ}+\mathrm{q} \sum \Delta \mathrm{G}_{\mathrm{B}}^{\circ})]\right.\right.}\end{array}

This requires the exact same treatment as \mathrm{\Delta H} or \mathrm{\Delta S}

 

Gibb's Free Energy Change for small changes in a Reversible process

\mathrm{G=H-TS}

\mathrm{dG=dH-TdS-SdT}\ \ \ \ \rightarrow (1)

Now, 

\mathrm{dH=dE + PdV + VdP}\ \ \ \ \rightarrow (2)

Using equations (1) and (2), we can write

\mathrm{dG=dE + PdV + VdP-TdS - SdT}\ \ \ \ \rightarrow (3)

Now, 

\mathrm{dE= dq +dw \ ; \ dq= TdS\ ; dw = -PdV}

Putting these values in the above expression (3), we have 

\mathrm{dG = VdP -SdT}

Note: Remember this important formula for small changes in dG values 

Spontaneity Criteria With Gibbs Energy (G)

and Criteria of Spontaneity

Suppose we consider a system which is not isolated from its surroundings then for such a system is given as:

\\ \mathrm{\ \Delta S_{total} = \ \Delta S_{system} +\ \Delta S_{surrounding} }

If we consider that qp amount of heat is given by the system to the surroundings at constant temperature and constant pressure then 

 \left(q_{\mathrm{p}}\right)_{\text { surroundings }}=-\left(\mathrm{q}_{\mathrm{p}}\right)_{\text { system }}=-\Delta \mathrm{H}_{\text { system }}
 

\Delta \mathrm{S}_{\text { surroundings }}=\frac{\left(\mathrm{q})_{\mathrm{p} \text { surroundings }}\right.}{\mathrm{T}}=\frac{-\Delta \mathrm{H}_{\text { system }}}{\mathrm{T}} \dots(ii)

From equation (i) and (ii)

\Delta \mathrm{S}_{\text { total }}=\Delta \mathrm{S}_{\text { system }}-\frac{\Delta \mathrm{H}_{\text { system }}}{\mathrm{T}}

Or

\mathrm{T\Delta \mathrm{S}_{\text { total }}=T\Delta \mathrm{S}_{\text { system }}-\Delta \mathrm{H}_{\text { system }}}

-\mathrm{T\Delta \mathrm{S}_{\text { total }}=\Delta \mathrm{H}_{\text { system }}-T\Delta \mathrm{S}_{\text { system }}}

As according to Gibb-Helmholtz equation,

\\ \mathrm{\ \Delta G = \Delta H - T\Delta S}

So, \\ \mathrm{\ \Delta G_{system} = \Delta H_{system} - T\Delta S_{system}}

\\ \mathrm{\ \Delta G_{system} =- T\Delta S_{total}}

As for spontaneous process

\\ \mathrm{\Delta S_{total} > 0}

Hence  \\ \mathrm{\Delta G = -ve}

Thus for a spontaneous process must be positive.

Or must be negative.

 

Case I.  Suppose both energy and entropy factors oppose a process that is,

\mathrm{= (+ ve) - (-ve) = +ve}

Thus, is positive for a non-spontaneous process.

 

  Case II.  Suppose both tendencies be equal in magnitude but opposite, that is,

\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=0

Thus, the process is said to be at equilibrium.

 

Case III.  Suppose entropy and energy, both factors are favourable for a process, that is,

\mathrm{= (-ve)-(+ve) = -ve}

Thus, this process is spontaneous at every temperature.


 

Remark

-

+

Always -ve

Spontaneous

+

-

Always +ve

Non-spontaneous

+

+

+ ve at low temp

Non-spontaneous

- ve at high temp

Spontaneous

-

-

- ve at low temp

Spontaneous

+ ve at high temp

Non-spontaneous

 

  • \mathrm{\Delta G=negative},  Spontaneous process

  • \mathrm{\Delta G=positive}, Non-spontaneous process

  • , Process in equilibrium

 

  • In exergonic reaction \mathrm{\Delta G=negative}

  • In endergonic reaction \mathrm{\Delta G=positive}

  • Temperature also play s an important role to decide the spontaneity of a process. A process which is not spontaneous at low temperature can become spontaneous at high temperature and vice-versa.


 

Gibbs Energy At Equilibrium

\begin{array}{l}{\text { Relationship between } \Delta \mathbf{G}^{\circ} \text { and Equilibrium }} {\text { constant }\left(\mathbf{K}_{\mathrm{eq}}\right)}\end{array}

\begin{array}{l}{\text { for a reversible reaction }} \\ {\qquad \mathrm{P}+\mathrm{Q} \rightleftharpoons \mathrm{R}+\mathrm{S}}\end{array}

\begin{array}{l}{\Delta \mathrm{G}, \Delta \mathrm{G}^{\circ} \text { and Reaction Quotient (Q) are related as }} \\ {\text { follows }} \\ {\qquad \Delta \mathrm{G}=\Delta \mathrm{G}^{\circ}+\mathrm{RT} \log _{\mathrm{e}} \mathrm{Q}} \\ {\text { as at equilibrium } \Delta \mathrm{G}=0}\end{array}

\begin{array}{l}{\mathrm{Q}=\mathrm{Keq}} \\ {0=\Delta \mathrm{G}^{\circ}+\mathrm{R} \mathrm{T} \log _{\mathrm{e}} \mathrm{Keq}} \\ {\Delta \mathrm{G}^{\circ}=-\mathrm{RT} \log _{\mathrm{e}} \mathrm{Keq}} \\ {\Delta \mathrm{G}^{\circ}=-2.303 \mathrm{RT} \log _{10} \mathrm{Keq}}\end{array}

 

Relationship between \Delta G or \Delta G^o with E or E^o:-

Free energy change \Delta G in an electrochemical cell can be related to electrical work done (E) in cell as follows 

\Delta G = -nFE

when we use standard conditions than 

\Delta G^o = -nFE^o

Here E^o= standard E.M.F of the cell

n = No. of moles of e- transferred 

F = Faraday's constant

 

Study it with Videos

Gibbs Energy And Change In Gibbs Energy
Spontaneity Criteria With Gibbs Energy (G)
Gibbs Energy At Equilibrium

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Books

Reference Books

Gibbs Energy And Change In Gibbs Energy

Chemistry Part I Textbook for Class XI

Page No. : 184

Line : 15

Spontaneity Criteria With Gibbs Energy (G)

Chemistry Part I Textbook for Class XI

Page No. : 184

Line : 1

E-books & Sample Papers

Get Answer to all your questions

Back to top