Pearson | PTE
Trusted by 3,500+ universities and colleges globally | Accepted for migration visa applications to AUS, CAN, New Zealand , and the UK
Kinetic energy of ideal gas is considered one of the most asked concept.
43 Questions around this concept.
A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to 00C. If it were to go up straight without colliding with any other molecules, how high it would rise ? Assume that the height attained is much less than radius of the earth. (kB is Boltzmann constant)
An molecule has rotational, translational and vibrational motions. If the RMS velocity of molecules in its gaseous phase is , is its mass and is Boltzmann constant, then its temperature will be :
When a flask containing Helium and Argon in the Ratio of 4:3 by mass. The Temperature of the mixture is . Find the ratio of average kinetic Energy per molecule of two gases.
NEET 2024: Cutoff (OBC, SC, ST & General Category)
NEET 2024 Admission Guidance: Personalised | Study Abroad
NEET 2025: Syllabus | Most Scoring concepts | NEET PYQ's (2015-24)
What is the Energy of diatomic gas whose pressure and density of the gas ?
What is the value of thermal velocity ms-1 of the Helium atom at room temperature?
A cylinder contains N moles of diatonic gas at Temperature T. Heat is supplied such that temperature remains constant but n moles of gas are converted to monoatomic gas. What will be the change in Kinetic Energy?
A gas has volume and pressure The total translational kinetic energy of all the molecules of the gas is -
Trusted by 3,500+ universities and colleges globally | Accepted for migration visa applications to AUS, CAN, New Zealand , and the UK
The graph which represents the variation of the mean kinetic energy of molecules with temperature C is -
At temperature, the kinetic energy of an ideal gas is . If the temperature is increased , then the kinetic energy will be -
The translational kinetic energy of a molecule of a gas, at temperature, is:
The kinetic energy of ideal gas-
In ideal gases, the molecules are considered as point particles. The point particles can have only translational motion and thus only
translational energy. So for an ideal gas, the internal energy can only be translational kinetic energy.
Hence kinetic energy (or internal energy) of n mole ideal gas
1. kinetic energy of 1 molecule
where k = Boltzmann’s constant
and
i.e Kinetic energy per molecule of gas does not depends upon the mass of the molecule but only depends upon the temperature of the gas.
2. kinetic energy of 1 mole ideal gas
i.e Kinetic energy per mole of gas depends only upon the temperature of the gas.
3. At T = 0, E = 0 i.e. at absolute zero the molecular motion stops.
As we know ......(1)
And K.E. per unit volume= ...... (2)
So from equation (1) and (2), we can say that
i.e. the pressure exerted by an ideal gas is numerically equal to the two-third of the mean kinetic energy of translation per unit volume of the gas.
According to this law, for any system in thermal equilibrium, the total energy is equally distributed among its various degrees of freedom.
I.e Each degree of freedom is associated with energy
1. At a given temperature T, all ideal gas molecules will have the same average translational kinetic energy as
2. Different energies of a system of the degree of freedom f are as follows
"Stay in the loop. Receive exam news, study resources, and expert advice!"