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10 Questions around this concept.
A volume cylinder is filled with 1 mol of gas at room temperature (300 K). The molecular diameter of , and its root mean square speed are found to be 0.3 nm and 200 m/s respectively. What is the average collision rate (per second) for an molecule?
The mean free path of molecules of a gas, (radius 'r') is inversely proportional to:
If the successive collision time interval of an ideal gas at a pressure of 2 atm and Temperature is 300 K is 6.0×10-8. What will be the new vision time if the pressure is doubled and the temperature is set to 500k?
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Consider an ideal gas continued in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increases as Where in the volume of the gas. The value of is
The mean free path of molecules of a gas (radius ) is inversely proportional to -
Mean Free Path -
On the basis of kinetic theory of gases, it is assumed that the molecules of a gas are continuously colliding against each other. So, the distance travelled by a gas molecule between any two successive collisions is known as free path.
There are assumption for this theory that during two successive collisions, a molecule of a gas moves in a straight line with constant velocity. Now, let us discuss the formula of mean free path -
Let be the distance travelled by a gas molecule during n collisions respectively, then the mean free path of a gas molecule is defined as -
Here, is the mean free path.
It can also be written as -
Now, let us take d = Diameter of the molecule,
N = Number of molecules per unit volume.
Also, we know that, PV = nRT
So, Number of moles per unit volume =
Also we know that number of molecules per unit mole =
So, the number of molecules in 'n' moles = nNA
So the number of molecules per unit volume is
So,
If all the other molecules are not at rest then,
Now, if and m = mass of each molecule then we can write -
So,
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