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Power Of Lens And Mirror MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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  • Power of lens and mirror is considered one of the most asked concept.

  • 15 Questions around this concept.

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A person can see clearly objects only when they lie between 50 cm and 400 cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be

For a normal eye, the cornea of the eye provides a converging power of 40 D, and the least converging power of the eye lens behind the cornea is 20 D. Using this information, the distance between the retina and the cornea-eye lens can be estimated by:

Two identical thin plano-convex glass lenses (refractive index 1.5) each having radius of curvature of 20 cm are placed with their convex surfaces in contact at the centre. The intervening space is filled with oil of refractive index 1.7. The focal length of the combination is:

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An achromatic convergent doublet has the power of +2D. If the power of the convex lens is + 5D, then the ratio of the dispersive powers of convergent and divergent lenses will be

A convergent lens of 6 diopters is combined with a diverging lens of -2 diopters. Find the power of combination.

An achromatic convergent doublet has the power of +2D. If the power of the convex lens is + 5D, then the ratio of the dispersive powers of convergent and divergent lenses will be:

The power of a convex lens is +5 \mathrm{D}\left(\mu_{\mathrm{g}}=1.5\right). When this lens is immersed in a liquid of refractive index \mu,  it acts like a divergent lens of focal length 100 \mathrm{~cm}. Then refractive index of the liquid will be

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Concepts Covered - 1

Power of lens and mirror

Power and lens and mirror-

Power of a lens is defined as the reciprocal of focal length and Power of a mirror is defined as the negative of reciprocal of focal length.

                                                        So, 

                                                                P_{Lens}=\frac{1}{f} \ \ \ and \ \ \ P_{Mirror} = \frac{-1}{f}  

                                                                                  Where, f = focal length

The unit of power is Diopter, 1D = 1 m-1

The sign of the focal length will be taken according to the sign convention which we have discussed in the previous concept. 

The power of a combination of lenses in contact is the algebraic sum of the powers of individual lenses, so it can be written as -

                                                             P_{Total } = P_{I}+P_{2}+P_{3}+\dots+P_{n}

 

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Power of lens and mirror

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