MAHE Manipal B.Sc Nursing 2025
ApplyAccorded Institution of Eminence by MoE, Govt. of India | NAAC A++ Grade | Ranked #4 India by NIRF 2024
Relative Velocity is considered one of the most asked concept.
25 Questions around this concept.
$A$ person $A$ is moving along east and $B$ is moving along north. Then relative velocity of $A$ with respect to $B$ is $\left(V_A=10 \mathrm{~m} / \mathrm{s}, V_B=10 \sqrt{3} \mathrm{~m} / \mathrm{s}\right)$
A particle is moving along a circular path with a constant speed of 10ms-1 . What is the magnitude of change in velocity of the particle, when it moves through an angle of 600 around the centre of the circle?
A container is kept in a moving bus.
A bus is moving at a speed of 10ms-1 on a straight road. A scooterist wishes to overtake the bus in 100s. If the bus is at a distance of 1km from the scooterist, with what speed should the scooterist chase the bus?
A man ( mass=50 kg ) and his son ( mass=20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of $0.70 \mathrm{~ms}^{-1}$ with respect to the man. The speed of the man (in $\mathrm{m} / \mathrm{s}$ ) with respect to the surface is :
Ship A is moving west at a speed of $10 \mathrm{~km} \mathrm{~h}^{-1}$, and ship B is moving north at a speed of 100 km south of $A$. The time at which the distance between them becomes shortest is:
Relative change in position of one object with respect to another object.
Formula-
Relative velocity of object A with respect to object B.
$\vec{V}_{A B}=\vec{V}_A-\vec{V}_B$
Case of Relative Velocity
When A and B are moving along a straight line in the same direction.
$$
\begin{aligned}
& \overrightarrow{V_A}=\text { Velocity of object } \mathrm{A} \text {. } \\
& \overrightarrow{V_B}=\text { Velocity of object } \mathrm{B} .
\end{aligned}
$$
Then, the relative velocity of $A$ w.r. $B$ is
$$
\begin{gathered}
\vec{V}_{A B}=\vec{V}_A-\vec{V}_B \\
\vec{V}_{A B}, \vec{V}_A, \vec{V}_B \text { all are in the same direction. }\left(\mid f \vec{V}_A>\vec{V}_{B)}\right.
\end{gathered}
$$
And Relative velocity of B w.r.t A is
$\begin{aligned} \vec{V}_{B A} & =\vec{V}_B-\vec{V}_A \\ \& \vec{V}_{A B} & =-\vec{V}_{B A}\end{aligned}$
When A & B are moving along with straight line in the opposite direction.
Relative velocity of A with respect to B is.
$\begin{aligned} & \vec{V}_{A B}=\vec{V}_A-\left(-\vec{V}_B\right) \\ & \vec{V}_{A B}=\vec{V}_A+\left(\vec{V}_B\right)\end{aligned}$
3. Relative Velocity when bodies moving at an angle $\theta$ to each other
Relative velocity of a body, A with respected body B
$$
\begin{aligned}
V_{A B} & =\sqrt{V_A^2+V_B^2+2 V_A V_B \cos (180-\theta)} \\
& =\sqrt{V_A^2+V_B^2-2 V_A V_B \cos (\theta)}
\end{aligned}
$$
$$
\begin{aligned}
V_A & =\text { velocity of } A \\
V_B & =\text { velocity of } B
\end{aligned}
$$
Where,
$$
\Theta=\text { angle between } A \text { and } B
$$
If $\overrightarrow{V_{A B}}$ makes an angle $\beta$ with the direction of $\overrightarrow{V_A}$, then
$$
\begin{aligned}
& \tan \beta=\frac{V_B \sin (180-\Theta)}{V_A+V_B \cos (180-\Theta)} \\
& =\frac{V_B \cdot \sin \Theta}{V_A-V_B \cos \Theta}
\end{aligned}
$$
If two bodies are moving at right angles to each other.
Relative Velocity of A with respect to B is
$V_{A B}=\sqrt{V_A^2+V_B^2}$
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