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Acceleration Of Block Against Friction MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Acceleration of block against friction is considered one of the most asked concept.

  • 14 Questions around this concept.

Solve by difficulty

Consider a car moving on a straight road with a speed of 100 m/s the distance (in meters) at which the car can be stopped is \left [ \mu _{k} = 0.5\right ]

Concepts Covered - 1

Acceleration of block against friction

 

  • Case 1:- Acceleration of a block on a horizontal surface

 

  • When the body is moving under application of force P, then kinetic friction opposes its motion.

              Let a is the net acceleration of the body.

       

           From the figure,

               ma = P - FK

        $a=\frac{P-F_K}{m}$

  • Case 2:- Acceleration of a block sliding down over a rough inclined plane

 

  • When the angle of the inclined plane is more than the angle of repose, the body placed on the inclined plane slides down with an acceleration a.

             

               From the figure,

$\begin{aligned} & m a=m g \sin \theta-F \\ & m a=m g \sin \theta-\mu R \\ & m a=m g \sin \theta-\mu m g \cos \theta \\ & a=[\sin \theta-\mu \cos \theta] \\ & \text { For } \mu=0 \quad \therefore \quad a=g \sin \theta\end{aligned}$

  • Case 3:- Retardation of a block sliding up over a rough inclined plane

 

  • When the angle of the inclined plane is less than the angle of repose, then for the upward motion

                               

$\begin{aligned} & m a=m g \sin \theta+F \\ & m a=m g \sin \theta+\mu m g \cos \theta \\ & m a=g[\sin \theta+\mu \cos \theta] \\ & a=g[\sin \theta+\mu \cos \theta] \\ & \text { For } \mu=0 \\ & a=g \sin \theta\end{aligned}$

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Acceleration of block against friction

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