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Heat And Power Developed In A Resistor MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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If the voltage across a bulb rated 220 volt - 100-watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is:

A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R

The charge flowing through a resistance R varies with time t as Q = at - bt2, where a and b are positive constants. The total heat produced in R is:

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Two electric bulbs have tungsten filaments of the same length. If one of them gives 60 \mathrm{~W} and the other 100 \mathrm{~W}, then

A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

A line having a total resistance of 0.5\Omega delivers \mathrm{15\: kW} at \mathrm{240W} to a small factory. The efficiency of transmission is near -

A capacitor of capacitance \mathrm{C} has \mathrm{Q}. It's connected to an identical capacitor through a resistance. Find heat produced in the resistance.
 

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An electric bulb rated for \mathrm{500 \mathrm{~W} \: at \: 100 \mathrm{~V}} is used in a circuit having \mathrm{200 \mathrm{~V}} supply. Find the resistance \mathrm{R} that must be put in series with the buck, so that the bulb draws \mathrm{500 \mathrm{~W}}.
 

A Storage battery with emf 15.6V loaded with external resistance produces a current 1A. In this case, the potential difference between the terminals of the storage battery equals 2.5 volts. Find the thermal power generated in the battery and the net power supplied by the battery for the external circuit.

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A current-carrying wire heats a metal rod. The wire provides a constant power (P) to the rod. The metal rod is enclosed in an insulated container it is observed that the temp (T) in the metal rod changes with time (t) as $T(t)=T_0\left(1+\beta t^{1 / 3}\right)$.The heat capacity of the metal is

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Heat and power developed in a resistor
  1. Heat and Power developed in a resistor

Heat developed in a resistor: When a steady current flows through a resistance R for time t, the loss in electric potential energy appears as increased thermal energy(Heat H) of resistor and H=i^2Rt

The power developed = \frac{energy}{time}=i^2R=iR=\frac{V^2}{R}      (from Ohm's law)

Unit of heat is the joule (J)

Unit of power is watt (W)

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Heat and power developed in a resistor

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