Travelling Sine Wave MCQ - Practice Questions with Answers

The equation of the wave is given by $y=0.5 \sin (100 t+25 x)$. The ratio of maximum particle velocity to wave velocity is

The equation of SHM is given by $y(x, t)=a_o \sin 2 \pi\left(v t-\frac{x}{\lambda}\right)$. If the maximum particle velocity is three times the wave velocity, the wavelength $\lambda$ of the wave is :

  A transverse wave is represented by

$y=\frac{10}{\pi} \sin \left(\frac{2 \pi}{T} t-\frac{2 \pi}{\lambda} x\right)$

For what value of the wavelength the wave velocity is twice the maximum particle velocity ?

The equation of traveling wave on a stretched string of linear density 5g/m is $y=0.003 \sin (450 t-9 x)$ where distance and time are measured in SI units. The tension in the string is: ( in newtons)

A transverse wave is represented by $y=A \sin (\omega t-k x)$. For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

At $\mathrm{t}=0$, a transverse wave pulse travelling in $+\mathrm{ve} x$-direction, with speed of $\frac{2}{3} \mathrm{~m} / \mathrm{s}$ by the function $y=\frac{6}{x^2}$ , $x \neq 0$. Transverse velocity of the particle at $\mathrm{x}=2 \mathrm{~m}$ and $\mathrm{t}=2 \mathrm{~s}$ is:

In a sine wave minimum distance between two particles having the same speed is always,

A plane progressive wave is given by $y=2 \cos 2 \pi(330 t-x)$. What is the period of the wave?

For the transverse wave equation, $y=A \sin (\pi x+\pi t)$, choose the correct option at t=0.

A transverse sinusoidal wave of amplitude $a$, wavelength $\lambda$ and frequency $n$ is travelling on a stretched string. The maximum speed of the particle is $\frac{1}{10} t h$ of the speed of propagation of the wave. If $a=10^{-3} \mathrm{~m}$ and $V=10 \mathrm{~m} / \mathrm{s}$, then $\lambda$ are given by -