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    Travelling Sine Wave MCQ - Practice Questions with Answers

    Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

    Quick Facts

    • Sine wave travelling on string is considered one the most difficult concept.

    • 11 Questions around this concept.

    Solve by difficulty

    The equation of the wave is given by $y=0.5 \sin (100 t+25 x)$. The ratio of maximum particle velocity to wave velocity is

    The equation of SHM is given by $y(x, t)=a_o \sin 2 \pi\left(v t-\frac{x}{\lambda}\right)$. If the maximum particle velocity is three times the wave velocity, the wavelength $\lambda$ of the wave is :

      A transverse wave is represented by

    $y=\frac{10}{\pi} \sin \left(\frac{2 \pi}{T} t-\frac{2 \pi}{\lambda} x\right)$

    For what value of the wavelength the wave velocity is twice the maximum particle velocity ?

    The equation of traveling wave on a stretched string of linear density 5g/m is $y=0.003 \sin (450 t-9 x)$ where distance and time are measured in SI units. The tension in the string is: ( in newtons)

    A transverse wave is represented by $y=A \sin (\omega t-k x)$. For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

    In a sine wave minimum distance between two particles having the same speed is always,

     

     

    A plane progressive wave is given by $y=2 \cos 2 \pi(330 t-x)$. What is the period of the wave?

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    For the transverse wave equation, $y=A \sin (\pi x+\pi t)$, choose the correct option at t=0.

     

    A transverse sinusoidal wave of amplitude $a$, wavelength $\lambda$ and frequency $n$ is travelling on a stretched string. The maximum speed of the particle is $\frac{1}{10} t h$ of the speed of propagation of the wave. If $a=10^{-3} \mathrm{~m}$ and $V=10 \mathrm{~m} / \mathrm{s}$, then $\lambda$ are given by -

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    Concepts Covered - 1

    Sine wave travelling on string

    The sine wave or sinusoid is a mathematical function that describes a smooth repetitive oscillation.

    $$
    y(t)=A \sin (\omega t+\phi)
    $$


    Here $\omega$, is the angular frequency i.e,

    $$
    \omega=\frac{2 \pi}{T}=2 \pi f_{\text {It defines how many cycles of the oscillations are there. }}
    $$

    and $\phi=$ phase angle

    General form:

    a spatial variable x that represents the position on the dimension on which the wave propagates, and a characteristic parameter k called wave number which represents the proportionality between the angular frequency ω and the linear speed (speed of propagation ) ν. which is 

    $y(x, t)=A \sin (k x-\omega t+\phi)$ when the wave is moving towards the right
    $y(x, t)=A \sin (k x+\omega t+\phi)$ when the wave is moving towards the left.
    The wavenumber is related to the angular frequency by:

    $$
    k=\frac{\omega}{v}=\frac{2 \pi f}{v}=\frac{2 \pi}{\lambda}
    $$


    Also,

    $$
    \begin{aligned}
    & \text { Particle velocity }=-(\text { wave velocity }) \times(\text { slope of } y \text { vs } \times \text { graph }) \\
    & \Longrightarrow V_p=-v\left(\frac{\partial y}{\partial x}\right) \\
    & \Longrightarrow \frac{\partial y}{\partial t}=-v\left(\frac{\partial y}{\partial x}\right)
    \end{aligned}
    $$
     

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    Sine wave travelling on string

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    Sine wave travelling on string

    Physics Part II Textbook for Class XI

    Page No. : 373

    Line : 30

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