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Energy Stored In Capacitor MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Quick Facts

  • Energy stored in capacitor is considered one the most difficult concept.

  • 30 Questions around this concept.

Solve by difficulty

If there are n capacitors in parallel connected to volt source, then the energy stored is equal to:

The work done in placing a charge of 8\times 10^{-18} coulomb on a condenser of capacity 100 micro-farad is

A fully charged capacitor has a capacitance C. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m. If the temperature of the block is raised by \Delta T, the potential difference V across the capacitance is

 

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be:

A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volt. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is

A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system:

Concepts Covered - 1

Energy stored in capacitor

Energy stored in capacitor:  When charge is added to a capacitor then charge already present on the plate repel any new incoming charge. Hence a new charge has to be sent by applying force and doing work on it. All this work done on charges become energy stored in the capacitor. If Q is the amount of charge stored when the whole battery voltage appears across the capacitor, then the  stored energy is obtained from the integral:

U=\int_{0}^{Q} \frac{q}{C} d q=\frac{1}{2} \frac{Q^{2}}{C}

This energy expression can be put in three equivalent forms by just permutations based on the definition of capacitance  C=\frac{Q}{V}.

U=\frac{1}{2} \frac{Q^{2}}{C}=\frac{1}{2} Q V=\frac{1}{2} C V^{2}

This energy is stored in the form of Electric field between the plates.

Energy density/Energy per unit volume :

 \mathrm{u}=\frac{1}{2} \mathrm{cv}^{2} / \mathrm{V}=\frac{1}{2} \frac{\varepsilon_{0} A E^{2} d^{2}}{d A d}

 \mathrm{u}=\frac{1}{2} \varepsilon_{0} E^{2}.

 

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Energy stored in capacitor

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