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Mole Concept Questions for NEET 2025 Exam: Mole Concept NEET Questions With Answer

Mole Concept Questions for NEET 2025 Exam: Mole Concept NEET Questions With Answer

Edited By Irshad Anwar | Updated on Mar 28, 2025 03:04 PM IST | #NEET
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Mole Concept Questions for NEET: The Mole Concept is very important for NEET Chemistry. It makes you understand things such as how much of a substance you possess and how it interacts with other substances. This concept is applied in numerous fields of chemistry.

To perform well in the NEET Exam, practice Mole Concept NEET questions. This will help you solve problems with ease and score well in Chemistry. Regular practice of the mole concept NEET previous year question paper will make you confident and prepared for the exam.

Why are Mole Concept Questions for NEET Important?

The mole concept is a bridge that lets you relate big things (such as grams) to small things (such as atoms). It's applied in lots of areas of chemistry, including:

  1. Mixing Things: Knowing how much of each thing is in a mixture.

  2. Chemical Reactions: Knowing how much of one thing becomes another.

  3. Gases: Know how gases work.

This Story also Contains
  1. Why are Mole Concept Questions for NEET Important?
  2. Types of Mole Concept Questions in NEET
  3. Mole Concept NEET Previous Year Question Paper
  4. How to Prepare for Mole Concept Questions
  5. Common Mistakes to Avoid
  6. Simple Tips for Success with Mole Concept NEET PYQ
Mole Concept Questions for NEET 2025 Exam: Mole Concept NEET Questions With Answer
Mole Concept Questions for NEET 2025 Exam: Mole Concept NEET Questions With Answer

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Background wave

Types of Mole Concept Questions in NEET

The types of questions asked about the mole concept NEET previous year question paper are discussed below:

1. Straight Conversion Problems

These examine simple concepts of mole-particle-mass relationships:

  1. Calculate atoms in 0.5 moles of oxygen

  2. Determine the number of moles in 49g H2S04

Key Formula:

1743154030255

1743154030299

2. Concentration Calculations

Focus on molarity, molality, normality, and their interconversions.

Examples:

  1. Find the molarity of 98% H2S04 (density = 1.84g/cc1.84g/cc).

  2. Prepare 250ml 2MHNO3 from 70% concentrated acid.

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Key Formula:

For molarity:

1743154030345

3. Stoichiometry and Limiting Reagents

These involve multi-step calculations using balanced chemical equations and mole ratios.

Examples:

  1. Determine the mass of CaCO3 needed to produce 11gCO2

  2. Identify the limiting reagent in N2+3H2→2NH3

Strategy:

Always verify mole ratios from the balanced equation before proceeding with calculations.

4. Empirical and Molecular Formulas

Combine mole concepts with percentage composition analysis.

Examples:

  1. A compound contains 40% C, 6.67% H, and 53.33% O. Find its empirical formula.

  2. Determine the molecular formula from combustion data.

Approach:

  1. Convert percentages into moles.

  2. Find the simplest whole-number ratio.

  3. Use molar mass to derive the molecular formula.

5. Gas Law Applications

These integrate Avogadro’s law and ideal gas equations.

Examples:

  1. Calculate the volume occupied by 2 moles O2 at STP.

  2. Determine molar mass from gas density measurements.

For non-STP conditions:

1743154030479

At STP:

1743154030438

Where:

  • P=Pressure (atm)

  • P=Pressure (atm),

  • V=Volume (L)

  • V=Volume (L),

  • n=Moles

  • n=Moles,

  • R=0.0821 L⋅atm/(mol⋅K)

  • R=0.0821L⋅atm/(mol⋅K),

  • T=Temperature (K)

  • T=Temperature (K).

Mole Concept NEET Previous Year Question Paper

Given below are some mole concept NEET questions:

(2021 NEET)

  1. Which of the following is the correct option for the right relationship between C_{p} and C_{v} for one mole of ideal gas?

Option 1:C_{p}+C_{v}=R

Option 2:C_{p}-C_{v}=R

Option 3:C_{p}=RC_{v}

Option 4:C_{v}=RC_{p}

Answer: The relation between C_p\ and\ C_v for one mole of an ideal gas is given as

C_P-C_V = R.

Hence, the answer is option (3).C_{p}=RC_{v}

2) The number of moles of electrons in 1 mole of NH₄⁺ is:

  1. 10

  2. 9

  3. 8

  4. 7

Answer: (2) 9

Explanation:

  • Atomic numbers: N = 7, H = 1

  • NH₄⁺ has (1N + 4H) = (7 + 4) = 11 electrons

  • Since NH₄⁺ loses one electron, total electrons = 10 electrons per molecule

  • For 1 mole of NH₄⁺, number of moles of electrons = 10 moles of electrons

Hence, the correct answer is option (2) 9 moles.

3) On applying repeated electric spark on 15 mL mixture of \mathrm{N}_2 \; \&\; \mathrm{CO}, it produced \mathrm{CO}_2\: \; \& \; \mathrm{NO}. For the process of combustion, 11 mL \mathrm{O}_2 was needed. Calculate mole % off \mathrm{CO} in the mixture. (All V are measured under similar conditions).

  1. 5.3

  2. 53.33

  3. 4.667

  4. 46.67

Answer: (2) 53.33

Explanation: The reactions involved are -

\mathrm{N}_2+\mathrm{O}_2 \rightarrow 2 \mathrm{NO}

\mathrm{CO}+\frac{1}{2} \mathrm{O}_2 \rightarrow \mathrm{CO}_2

Let x mL be the volume of the 15 mL mixture

The total volume of \mathrm{O_2} required \mathrm {=x+\frac{15-x}{2}=11}

\begin{aligned} & \mathrm{2 x+15-x=22 }\\ \\& \mathrm{x=22-15=7} \end{aligned}

Volume of \mathrm{CO}=15-7

= 8 \; \mathrm{mL}

Mol % of \mathrm{CO}=\frac{8}{15}\times 100

=53.33%

Hence, the answer is the option (2).

4) For a given 1 mole of ideal gas kept at 3.5 atm in a container at capacity 4.463 I , the Avagadro proportionality constant for the hypothesis (see figure) (NEET 20221)

1743154032223

  1. 1)2.46

  2. 1.275

  3. 4.667

  4. 46.67

Answer: 2)1.275

Explanation: According to Avogadro's hypothesis

Vαn

V=n(RT)P

 proportionality constant =RTp Using Pv=nRTRTp=Vn=4.4633.5=1.275

Hence, the answer is the option (2).

5) Assertion: The volume of a gas and the number of moles of gas have an inverse relationship, meaning that as the number of moles of gas increases, the volume of the gas will decrease, and vice versa.

Reason: The ratio by volume of gaseous reactants and products is in relation to their mole ratio.

  1. Both assertion and reason are true, and the reason is the correct explanation of the assertion.

  2. Both assertion and reason are true, but the reason is not the correct explanation of the assertion

  3. The assertion is true, but the reason is false.

  4. The assertion is false, but the reason is true.

Answer: 2) Both assertion and reason are true, but the reason is not the correct explanation of the assertion

Explanation: The assertion and reason both are correct and related to each other, but they are not directly dependent on each other. Let's break them down:

Assertion: The volume of a gas is inversely proportional to the number of moles of gas.

This assertion is correct according to Avogadro's Law, which states that, at a given temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas. In other words, as the number of moles of gas increases, the volume of the gas decreases proportionally, and vice versa.

Reason: The ratio by volume of gaseous reactants and products is in agreement with their mole ratio.

This reason is related to the stoichiometry of chemical reactions. The mole ratio of reactants and products in a balanced chemical equation determines the ratio of their volumes at a given temperature and pressure, assuming they are all gases. This is known as the Volume Ratio Law or Gay-Lussac's Law. Therefore, the ratio of volumes of gaseous reactants and products is in agreement with their mole ratio.

Overall, the assertion and reason are both correct and related, but the reason is not necessarily required to prove the assertion.

Hence, the answer is the option (2).

How to Prepare for Mole Concept Questions

Here are some steps to prepare from mole concept neet pyq:

Step 1: Understand the Basics

Know what a mole is and how to change from one unit to another.

Step 2: Practice Problems

Practice many mole concept neet pyq to become excellent at solving questions.

Step 3: Use mole concept NEET pyq

Solve Mole Concept NEET past years’ papers to understand what type of questions are being asked.

Step 4: Watch Video Lessons

Watch videos that define the mole concept in simple terms.

Common Mistakes to Avoid

Some common mistakes that need to be avoided while practising the mole concept neet pyq are:

  1. Confusing Units: Ensure you understand the difference between molarity and molality.

  2. Forgetting Avogadro's Number: Apply it only for particle counting while practising mole concept questions for NEET.

  3. Not Checking for Limiting Reagents: Always observe which chemical is used up first in a reaction.

Simple Tips for Success with Mole Concept NEET PYQ

Here are some important tips while practising mole concept NEET questions:

  1. Practice daily: Do a few mole concept questions for NEET daily.

  2. Use Simple Language: Don't bother with difficult words; just understand.

  3. Ask for Help: If you’re stuck, ask a teacher or friend.

Mastering the Mole Concept is important for NEET Chemistry. The practice of Mole Concept NEET questions consistently builds a good foundation. Solution of Mole Concept NEET previous year question papers (PYQs) provide an insight into key concepts and exam patterns. Through the practice of Mole Concept NEET PYQ, the accuracy and speed of solving problems can be enhanced. Work on clarity in concepts and try different Mole concept questions for NEET to build confidence. Revising regularly and doing mock tests will improve your performance in the exam.

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Questions related to NEET

Have a question related to NEET ?

Hello dear,

To get admission to a BAMS course without NEET, here are a few possible routes:

  1. State-Level Exams: Some states, like Karnataka, Maharashtra, or Uttarakhand, may conduct their own entrance exams for BAMS admissions. These may not require NEET scores.

  2. Private Colleges & Management/NRI Quota: Some private colleges may offer admission through management or NRI quotas without requiring NEET scores, although the fees may be higher.

  3. Special Exemptions: Rarely, some colleges may offer exemptions or internal entrance exams, but this is not common.

Make sure the college is recognized by (CCIM) to ensure the degree is valid. Always verify the latest admission guidelines from the specific state or college.

Dear

If you're looking to pursue a BSc in Microbiology from a government college without appearing for NEET or CUET, you can still explore many excellent options. Most government colleges admit students to BSc courses based on the marks obtained in your 12th-grade exams. Here are some of the top government colleges you can consider for BSc in Microbiology:

1. University of Delhi (DU)

  • Courses: DU offers a BSc (Hons) in Microbiology.
  • Admission Process: Based on 12th-grade marks and cutoffs, which vary every year.
  • Eligibility: You need to have Biology as a subject in Class 12 and meet the cutoff requirements.

2. Banaras Hindu University (BHU)

  • Courses: BHU offers a BSc in Microbiology.
  • Admission Process: Admission is usually based on the entrance test, but if you’re looking for colleges with direct 12th marks-based admission, consider other options.
  • Eligibility: A science background with Biology in Class 12 is required.

3. University of Calcutta

  • Courses: BSc in Microbiology.
  • Admission Process: Based on merit (your 12th-grade marks).
  • Eligibility: Completion of Class 12 with Biology as one of the subjects.

4. Jamia Millia Islamia (JMI)

  • Courses: BSc in Microbiology.
  • Admission Process: Based on 12th marks or an entrance exam, depending on the course.
  • Eligibility: Biology should be one of the subjects in Class 12.

5. Madras University

  • Courses: BSc in Microbiology.
  • Admission Process: Based on merit, considering your marks in 12th.
  • Eligibility: A science background in Class 12 with Biology.

6. University of Pune (Savitribai Phule Pune University)

  • Courses: BSc in Microbiology.
  • Admission Process: Based on 12th-grade marks.
  • Eligibility: Biology as a subject in Class 12.

7. Karnataka University, Dharwad

  • Courses: BSc in Microbiology.
  • Admission Process: Based on marks obtained in the Class 12 exam.
  • Eligibility: Class 12 with a science background and Biology as a subject.

8. St. Xavier’s College, Mumbai

  • Courses: BSc in Microbiology.
  • Admission Process: Based on Class 12 marks.
  • Eligibility: Science stream with Biology in 12th.

9. Aligarh Muslim University (AMU)

  • Courses: BSc in Microbiology.
  • Admission Process: Based on entrance tests or merit, depending on the course.
  • Eligibility: Completion of Class 12 with Biology.

10. Sri Venkateswara College, Delhi University

  • Courses: BSc (Hons) Microbiology.
  • Admission Process: Based on Class 12 marks through the DU admission process.
  • Eligibility: Class 12 with Biology as a subject.

Tips:

  • Research and Apply Early: Keep an eye on the official websites for admission dates and specific criteria.
  • Check Cutoffs: Colleges like DU and BHU release cutoff lists, which are based on your 12th-grade performance. Ensure you meet the required percentage.
  • Prepare Documents: Make sure to have your Class 12 marksheet and necessary documents ready for the application.

These colleges offer great opportunities for pursuing BSc in Microbiology, and you do not need to appear for NEET or CUET for admission to these programs.

Here’s the cutoff information of neet 2025 for general students:-

  • NEET 2025 cut-off : Official cut-off marks for General students will be released after the NEET 2025 results.
  • Expected range : The anticipated cut-off for General (UR/EWS) students is likely to fall between 720-162 marks, based on previous trends.

  • Percentile requirement : A minimum of 50th percentile is required for General category candidates to qualify.

  • Factors influencing the cut-off :

    • Difficulty level of the exam

    • Number of candidates appearing

    • Seat availability across medical colleges

  • Final announcement : The official cut-off will be published by NTA after the NEET results are processed.

The NEET 2025 application fees were as follows:


General Category: Rs1,700


General-EWS/OBC-NCL: Rs1,600

SC/ST/PwBD/Third Gender: Rs1,000

Candidates appearing from outside India were required to pay a higher fee of Rs9,500.

The application fee was payable online through various modes, including debit card, credit card, net banking, UPI, or e-wallet.

Hello,

As of March 2025, the NEET application fees are:

- General Category:1,700

- General-EWS/OBC-NCL:1,600

- SC/ST/PwD/Third Gender:1,000

- NRI Candidates:9,50

Fees are payable online via net banking, credit/debit cards, or UPI.

hope this helps you,

Thank you

View All

Column I ( Salivary gland)

 

Column II ( Their location)

Parotids

I

Below tongue

Sub-maxillary / sub-mandibular

Ii

Lower jaw

Sub-linguals

Iii

Cheek

Option: 1

a(i), b(ii) , c(iii)

 


Option: 2

a(ii), b(i), c(iii)

 


Option: 3

a(i), b(iii), c(ii)


Option: 4

a(iii), b(ii), c(i)


Ethyl \; ester \xrightarrow[(excess)]{CH_{3}MgBr} P

the product 'P' will be ,

Option: 1


Option: 2


Option: 3

\left ( C_{2}H_{5} \right )_{3} - C- OH


Option: 4


 

    

           

 Valve name                            

             

Function

    I   Aortic valve     A

Prevents blood from going backward from the pulmonary artery to the right ventricle.

    II   Mitral valve     B

 Prevent blood from flowing backward from the right ventricle to the right atrium.

    III   Pulmonic valve     C

 Prevents backward flow from the aorta into the left ventricle.

    IV   Tricuspid valve     D

 Prevent backward flow from the left ventricle to the left atrium.

 

Option: 1

I – A , II – B, III – C, IV – D


Option: 2

 I – B , II – C , III – A , IV – D


Option: 3

 I – C , II – D , III – A , IV – B


Option: 4

 I – D , II – A , III – B , IV – C 

 

 


Column A Column B
A

a) Organisation of cellular contents and further cell growth.  

B

b) Leads to formation of two daughter cells.

C

c) Cell grows physically and increase volume proteins,organells.

D

d)  synthesis and replication of DNA.

Match the correct option as per the process shown in the diagram. 

 

 

 

Option: 1

1-b,2-a,3-d,4-c
 


Option: 2

1-c,2-b,3-a,4-d


Option: 3

1-a,2-d,3-c,4-b

 


Option: 4

1-c,2-d,3-a,4-b


0.014 Kg of N2 gas at 27 0C is kept in a closed vessel. How much heat is required to double the rms speed of the N2 molecules?

Option: 1

3000 cal


Option: 2

2250 cal


Option: 3

2500 cal


Option: 4

3500 cal


0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The modecular weight of the acid will be

Option: 1

32


Option: 2

64


Option: 3

128


Option: 4

256


0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:

Option: 1

31.75


Option: 2

15.8


Option: 3

47.4


Option: 4

63.5


0.5 g of an organic substance was kjeldahlised and the ammonia released was neutralised by 100 ml 0.1 M HCl. Percentage of nitrogen in the compound is

Option: 1

14


Option: 2

42


Option: 3

28


Option: 4

72


0xone is

Option: 1

\mathrm{KO}_{2}


Option: 2

\mathrm{Na}_{2} \mathrm{O}_{2}


Option: 3

\mathrm{Li}_{2} \mathrm{O}


Option: 4

\mathrm{CaO}


(1) A substance  known as "Smack"

(2) Diacetylmorphine

(3) Possessing a white color

(4) Devoid of any odor

(5) Crystal compound with a bitter taste

(6) Obtained by extracting from the latex of the poppy plant

The above statements/information are correct for:

Option: 1

Morphine


Option: 2

Heroin


Option: 3

Cocaine


Option: 4

Barbiturates


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