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Law of Equivalence MCQ - Practice Questions with Answers
Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET
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9 Questions around this concept.
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MEDIUMIn an experiment it showed that 10 ml of 0.05M solution of chloride required 10 mL of 0.1 M solution of AgNO3 , which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):
20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample ?
(At. Wt. : Mg = 24)
Which of the following statements is true regarding n factor?
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20 ml of $\mathrm{H}_3 \mathrm{PO}_4$ solution needs 40 ml of 0.1 M NaOH NaOH to convert it into sodium dihydrogen phosphate. How much volume of $0.1 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_2$ are needed to neutralize the same volume of the same $\mathrm{H}_3 \mathrm{PO}_4 $ completely
Concepts Covered - 1
Law of Equivalence
Laws of Equivalence
According to the law of equivalence, for each and every reactant and product,
Equivalents of each reactant reacted = Equivalents of each product formed.
Example,
Suppose the reaction is taking place as follows:
According to the law of equivalence,
Equivalents of P reacted = Equivalents of Q reacted = Equivalents of R produced = Equivalents of S produced
Equivalents of any substance = (Weight of substance (in g)) / (Equivalent weight)
= Normality (N) x Volume (V) (In litre)
Normality (N) = n-Factor x Molarity (M)
Law of Equivalence finds great importance in Acid base Neutralisation Reactions as well as Redox Titrations.
Here we shall be mainly covering the Acid Base neutralisation reactions in detail.
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