Ammeter is considered one the most difficult concept.
29 Questions around this concept.
A galvanometer having a coil resistance of 100 gives a full scale deflection, when a current of 1 mA is passed through it. The value of the resistance (in $\Omega$ ) which can convert this galvanometer into ammeter giving a full scale deflection for a current of 10 A , is :
Ammeter
It is a device used to measure current and always connected in series with the circuit

In the above circuit, A represents the ammeter.
Conversion of galvanometer into ammeter: Connect a low resistance (shunt) in parallel to the galvanometer.

Gs
- The equivalent resistance of the combination is $\overline{G+s}$ where G is the galvanometer resistance and s is the shunt resistance.
- Required shunt
$
s=\frac{i_g G}{\left(i-i_g\right)} . \text { Where } \mathrm{i} \text { is the total current, } i_g \text { is the galvanometer current }
$
- To pass $n^{\text {th }}$ part of main current through galvanometer that is If $i_g=i / n$
Then the required shunt resistance
$
s=\frac{G}{(n-1)}
$
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