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    Archimedes Principle MCQ - Practice Questions with Answers

    Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

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    • 41 Questions around this concept.

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    A leak proof cylinder of length 1 m , made of a metal which has very low coefficient of expansion is floating vertically in water at $0^{\circ} \mathrm{C}$ such that its height above the water surface is 20 cm . When the temperature of water is increased to $4^{\circ} \mathrm{C}$, the height of the cylinder above the water surface becomes 21 cm . The density of water at $T=4^{\circ} \mathrm{C}$, relative to the density at $T=0^{\circ} \mathrm{C}$, is close to :

     A load of mass M kg is suspended from a steel wire of length 2 m and radius 1.0 mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 mm. Now the load is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8. The new value of increase in length (in mm) of the steel wire is :

    A block of wood floats in a liquid with four-fifths of its volume submerged. If the relative density of wood is 0.8, what is the density of the liquid in units of  \mathrm{\mathrm{kg} \, \mathrm{m}^{-3}}?

    A block of wood floats in a liquid in a beaker with \mathrm{3 / 4^{\text {th }}} of its volume submerged under the liquid. If the beaker is placed in an enclosure that is falling freely under gravity, the block will

    A cubical block of steel on each side equal to l is floating on mercury in a vessel. The densities of steel and mercury are \mathrm{\rho_s} and \mathrm{\rho_m}. The height of the block above the mercury level is given by

    A cube of ice is floating in water contained in a vessel. When the ice melts, the level of water in the vessel

    A cube of ice is floating in a liquid of a relative density of 1.25 contained in a beaker. When the ice melts, the level of the liquid in the beaker

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    A cubical vessel of height \mathrm{1 \mathrm{~m}} is full of water. What is the amount of work done in pumping water out of the vessel? \mathrm{Take \, \, g=10 \mathrm{~ms}^{-2}.}

    A piece of ice, with a stone frozen inside it, is floating in water contained in a beaker. When the ice melts, the level of water in the beaker

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    A balloon of mass m contains water of mass M. If it is completely immersed in water, the apparent mass of the balloon with water in it will be

    Concepts Covered - 1

    Archimedes principle

    Archimede's principle states that when a body is immersed partly or wholly in a fluid, then the liquid exerts an upward force/upthrust/buoyant force on the body which is equal to the weight of the fluid displaced by the body.

    Buoyant force-

    • The buoyant force is given as 

    $$
    F_B=\rho V g
    $$


    Where,

    $F_B=$ Buoyant force
    $\rho=$ density of the fluid
    $V=$ Volume of the solid body immersed in the liquid or Volume of the fluid displaced
    As $\rho=\frac{m}{V}$
    So we can write $F_B=m g_{=\text {weight of the fluid displaced }}$

    Where m=mass of the fluid displaced

    • The buoyant force acts vertically upwards (opposite to the weight of the body)

    • The buoyant force is independent of mass, size, and the density of the body inside the fluid.

    • The buoyant force depends upon the nature/density of the displaced fluid. 

                  Apparent weight-

    • Apparent weight=(Actual  weight)-(Buoyant force)

    • The apparent weight of the body of density (\rho) when immersed in a liquid of density     (\sigma) is given by          

    $$
    \begin{aligned}
    & \quad W_{a p p}=W-F_B=V \rho g-V \sigma g=V \rho g\left(1-\frac{\sigma}{\rho}\right) \\
    & W_{a p p}=W\left(1-\frac{\sigma}{\rho}\right)
    \end{aligned}
    $$


    Where $W=$ Actual weight of the body
    $V=$ volume of the body immersed in a liquid
    From this, we can say that
    If a body of volume V is immersed in a liquid of density ( $\sigma$ ) Then its weight reduces
    And Loss in weight is given by

    $$
    W_{l o s s}=W-W_{a p p}=V \sigma g
    $$
     

    • The relative density of a body

                  R.D $=\frac{\text { density of body }}{\text { density of water }}$

    • Floatation-

    When a body of density $\rho$ is immersed in a liquid of density $\sigma$,
    Then the body will float if the buoyant force on the body is equal to the weight of the fluid displaced by the body. This means the body is in equilibrium.
    1. If the density of the body is equal to that of liquid i.e $\rho=\sigma$

    Then the Weight of the body will be equal to the upthrust.
    And the body will float but the body will fully be submerged in liquid.
    2. If the density of the body is less than that of liquid $\rho<\sigma$

    Then the Weight of the body will be less than upthrust.
    And the body will float but the body will partially be immersed in liquid.
    If the density of the body is greater than that of liquid $\rho>\sigma$
    Then the Weight of the body will be greater than the upthrust So the body will sink.

     

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    Archimedes principle

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