13 Questions around this concept.
An experiment takes 10 minutes to raise the temperature of water in a container from 00C to 1000C and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking the specific heat of the water to be 1 cal/g 0C, the heat of vapourization according to this experiment will come out to be :
Equal masses of two substances of densities and
are mixed. The density of the mixture would be
Equal volumes of two substances of densities and
are mixed. The density of the mixture would be
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of
at
is mixed with
of
at
. The temperature of the mixture is -
Principle of Calorimetry -
Calorimetry means 'measurement of heat'.
When two bodies (both being liquid or one being solid and other liquid) at different temperatures are mixed or come in contact, heat will be transferred from a body at a higher temperature to a body at a lower temperature till both acquire the same temperature. The body at a lower temperature absorbs heat while body at a higher temperature releases it.
The principle of calorimetry represents the law of conservation of heat energy.
The temperature of the mixture always lies between the temperature of the liquid having lowest temperature and the temperature of the liquid having highest temperature.
Mixing of two substances when the temperature changes only. It means no phase change. Suppose two substances have masses
$$
\begin{aligned}
& \text { Hence, Heat lost }=\text { Heat gained } \\
& \Rightarrow m_1 c_1\left(\theta_1-\theta_{\max }\right)=m_2 c_2\left(\theta_{\text {mix }}-\theta_2\right) \\
& \theta_{\max }=\frac{m_1 c_1 \theta_1+m_2 c_2 \theta_2}{m_1 c_1+m_2 c_2}
\end{aligned}
$$
Similarly, we can derive formulas for different cases. The different cases and its result is mentioned in the table given below -

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